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Mathematics 7 Online
OpenStudy (anonymous):

Calculus. Please help me and I will give you medals.

OpenStudy (anonymous):

OpenStudy (anonymous):

@loser can you help me?

OpenStudy (anonymous):

@mathmale @freckles

OpenStudy (danjs):

i used the calculator and got it, is that all you need to know is how to type it in

OpenStudy (anonymous):

but that's at the second derivative. They gave me the original function. Then I need to derive it to cancel the integral and then I need to drive it again to find the second derivative, but I need help on the limits of this function. How do would you plug the limits after you derive the integral?

OpenStudy (anonymous):

derive*

OpenStudy (anonymous):

I got sec(4x^2)*8x as the second derivative, but it doesn't give me any of the values.

OpenStudy (anonymous):

I know you can just plug it in the calculator, but I need to know how to get the answer

OpenStudy (freckles):

what did you get for F'(x)?

OpenStudy (freckles):

hint use fundamental theorem of calculus

OpenStudy (danjs):

F ' (x) = 2*tan(4x^2)

OpenStudy (anonymous):

I got, tan(4x^2)

OpenStudy (anonymous):

how did you get the 2?

OpenStudy (freckles):

and you didn't find the derivative of the limit there... \[F(x)=\int\limits_0^{a(x)}g(t) dt \\ F(x)=G(t)|_0^{a(x)} \\ \text{ assume } G'=g \\ F(x)=G(a(x))-G(0) \\ \text{ differentiate both sides }\]

OpenStudy (freckles):

I used chain rule for the first term and constant rule for the second term

OpenStudy (freckles):

\[ F'(x)=[G(a(x))]'-[G(0)]' \\ F'(x)=a'(x)G'(a(x))-0 \\ F'(x)=a'(x)g(a(x))\]

OpenStudy (anonymous):

okay I see. I forgot the chain rule.

OpenStudy (danjs):

oh isee, calc for the decimal approx answer, i figured just type the thing into a computer algebra system and hit enter.. hah

OpenStudy (anonymous):

i know it, but I forgot to apply it

OpenStudy (freckles):

so @DanJS has actually given you the correct F' and now F'' should be easy to find

OpenStudy (anonymous):

i got sec^2(4x^2)*16x

OpenStudy (freckles):

oh and actually your earlier F'' @Joseluess was almost there you just needed a multiple of 2 there so great job and this F'' is like totally right now

OpenStudy (freckles):

you will definitely get one of the answers after plugging in 1

OpenStudy (freckles):

make sure your calc is in radians

OpenStudy (anonymous):

16.078 and yes it is. Thank you

OpenStudy (freckles):

no no

OpenStudy (freckles):

your calc is in degrees

OpenStudy (freckles):

put in radians you can do this by choosing mode

OpenStudy (anonymous):

wait, it is in degrees

OpenStudy (anonymous):

37.44

OpenStudy (freckles):

cool stuff

OpenStudy (danjs):

yeah radians is like 37.4

OpenStudy (anonymous):

is that correct?

OpenStudy (freckles):

yep you are right I got like 37.4488blahblah

OpenStudy (anonymous):

haha thanks both of you goys.

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