Mathematics
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OpenStudy (anonymous):
Find all values of x in the interval [0, 2π] that satisfy the equation. (Enter your answers as a comma-separated list.)
18 + 9 cos(2x) = 27 cos(x)
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OpenStudy (xapproachesinfinity):
hint subtract 27cosx from both side
OpenStudy (xapproachesinfinity):
i bring to a point where it is easy to do
9cos2x-27cosx+18=0
cos2x-3cosx+2=0
OpenStudy (xapproachesinfinity):
cos2x=2cos^2x-1
OpenStudy (xapproachesinfinity):
so we have 2cos^2x-3cosx+1=0
OpenStudy (xapproachesinfinity):
surely you can do an equation like this 2x^2-3x+1=0
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OpenStudy (xapproachesinfinity):
can you?
OpenStudy (anonymous):
Aha, Thank you very much for replying. Let me try it and get back to you
OpenStudy (xapproachesinfinity):
ok
OpenStudy (anonymous):
I get it until 2cos^2x-3cosx+1=0
OpenStudy (xapproachesinfinity):
alright
now we just think of that as 2r^2-3r+1=0
for now we forgot that cosx like we replaced with r
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OpenStudy (anonymous):
okay...
OpenStudy (xapproachesinfinity):
2r^2-3r+1=0 is just quadratic equation
OpenStudy (anonymous):
ohh I see...
OpenStudy (anonymous):
okay so r = 1/2 or 1 yeah?
OpenStudy (xapproachesinfinity):
you solve for r just as you usually do
-factoring
-quadratic formula
-completing the square
i don't know what other stuff you can use lol
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OpenStudy (xapproachesinfinity):
yes seems good
OpenStudy (anonymous):
lol...okay, so replacing r with cos will result in...?
OpenStudy (xapproachesinfinity):
if i did factoring we get (2r-1)(r-1)=0
which agrees with what you got
r=1/2 and r=1
we replace r by cosx
cosx=1/2 and cosx=1
OpenStudy (xapproachesinfinity):
now you think of all possible angles that give 1/2 and 1
from 0 to 2pi
OpenStudy (xapproachesinfinity):
forr what angles do we have cos =1/2?
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OpenStudy (anonymous):
60
OpenStudy (xapproachesinfinity):
yes
OpenStudy (anonymous):
and cos 0 = 1
OpenStudy (xapproachesinfinity):
not onnly 0 though
OpenStudy (xapproachesinfinity):
360 too
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OpenStudy (anonymous):
in radians that will be pi/3...I mean for 60...yeah?
OpenStudy (xapproachesinfinity):
yeah
OpenStudy (anonymous):
yeah...360 too
OpenStudy (xapproachesinfinity):
360 or 2pi in radian
OpenStudy (anonymous):
that will be 2pi
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OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
cos 300...5pi/3
OpenStudy (xapproachesinfinity):
then x=0,pi/3,2pi
OpenStudy (anonymous):
that gives 1/2 yeah?
OpenStudy (xapproachesinfinity):
we only need values from 0 to 2pi and we stop
we don;t need other rotations
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OpenStudy (anonymous):
yeah...but 5pi/3 is actually smaller than 2pi
OpenStudy (xapproachesinfinity):
i was giving you how to put it as a complete answer with commas as they asked
x=0,pi/3, 2pi
OpenStudy (xapproachesinfinity):
oh yeah right that has cos =1/2 too
correct i missed that one
OpenStudy (xapproachesinfinity):
good catch
OpenStudy (anonymous):
Yeah
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OpenStudy (anonymous):
THANK YOU SO SO SO MUCH...I AM REALLY GREATFUL!!!! :-)
OpenStudy (xapproachesinfinity):
no problem
OpenStudy (anonymous):
:-)
OpenStudy (xapproachesinfinity):
until next time :) thanks for the testimonial
OpenStudy (anonymous):
Sure!!! :-D
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OpenStudy (anonymous):
Please fan me so I can send you messages...If you don't mind though! @xapproachesinfinity
OpenStudy (xapproachesinfinity):
sure :)
OpenStudy (anonymous):
Thank You :-)...@xapproachesinfinity