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The mass of a copper atom is 1.06 ✕ 10−25 kg, and the density of copper is 8920 kg/m3. (a) Determine the number of atoms in 1 cm3 of copper.
Convert your density to kg/cm^3 then divide my the mass of an atom.
here is my reasoning: we have 8.93 grams of copper in 1 cm3, now the atomic mass of copper is 63.5, so, we have: \[\frac{{8.93}}{{63.5}} = ...?\] moles of copper in 1 \(cm^3\), therefore, we have: \[\frac{{8.93}}{{63.5}} \cdot 6.023 \cdot {10^{23}} = ...?\] atoms of copper in 1 \(cm^3\), being: \[{N_A} = 6.023 \cdot {10^{23}}\] the number of Avogadro
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