Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (imsleeziboii):

MATH HELP

OpenStudy (sagewilson):

Math question is required.

OpenStudy (imsleeziboii):

simplify the expression (4x^2y^3)^3

OpenStudy (sagewilson):

wait does it say that 4x has the power of 2y?

OpenStudy (imsleeziboii):

No

OpenStudy (imsleeziboii):

its 4x^2 y^3

OpenStudy (sagewilson):

oh okay, that makes more sense.

OpenStudy (sagewilson):

if you were to put y times itself 3 times, it would give you 3Y. And just multiply 4 by 4 and put an x behind the answer. It would look like this: __x 3Y, but then you'd have to do power of 3 again to each. so the product of 4 x 4 = ? times itself 3 times, and same with 3y

OpenStudy (imsleeziboii):

4096 and 27

OpenStudy (sagewilson):

if that's not an answer choice then I think it might be 16x 3y ^3

OpenStudy (mathstudent55):

\((4x^2y^3)^3 \) When you raise a power to a power, multiply powers.

OpenStudy (imsleeziboii):

sage would you like the choices?

OpenStudy (sagewilson):

yeah that'd help

OpenStudy (mathstudent55):

For example: \(\Large (x^3)^4 = x^{3 \times 4} = x^{12}\)

OpenStudy (sagewilson):

@mathstudent55 so they would be changed from (4x^2 y^3) to (4x^6 y^9) right?

OpenStudy (mathstudent55):

Also, if you have a product raised to a power, raise every factor to the power. For example: \(\Large (xyz)^2 = x^2 y^2 z^2\)

OpenStudy (imsleeziboii):

A .12x^5 y^6 B. 7x^5 y^6 C. 64x^6 y^6 D. 64x^6 y^9

OpenStudy (mathstudent55):

Keep the two rules above in mind. Here they are again: To raise a product to a power, raise every factor to the power. To raise a power to a power, multiply exponents.

OpenStudy (mathstudent55):

Here is the problem: \((4x^2y^3)^3 \) Let's apply the rule of the power of a product first. Every factor is raised to the power 3. \(=4^3(x^2)^3(y^3)^3 \) Do you understand so far?

OpenStudy (imsleeziboii):

yes

OpenStudy (mathstudent55):

@SageWilson You were close, but the 4 also is raised to the 3rd power.

OpenStudy (sagewilson):

I did not know that. Thank you for enlightening me :)

OpenStudy (imsleeziboii):

so would it be A.?

OpenStudy (mathstudent55):

Now we apply the second rule. To raise a power to a power, multiply powers. \(= 64x^6y^9\)

OpenStudy (mathstudent55):

Remember that an exponent is not a number you multiply by. An exponent tells you how many of the number in the base you need to multiply together.

OpenStudy (imsleeziboii):

correct

OpenStudy (mathstudent55):

\(4^3 \ne 4 \times 3\) \(4^3 = 4 \times 4 \times 4\)

OpenStudy (imsleeziboii):

ok

OpenStudy (mathstudent55):

A is not correct because 4^3 is not 12. Also, in choice A, the exponents of x and y were added to the outer exponent 3. That is incorrect. The exponents of x and y must be multiplied by the outer exponent 3.

OpenStudy (imsleeziboii):

okay so i ruled out A

OpenStudy (mathstudent55):

You don't need to rule any choice out. Just find the correct answer and match it to the correct choice.

OpenStudy (imsleeziboii):

I don't understand it

OpenStudy (mathstudent55):

Here it is again, step by step. |dw:1453405241830:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!