Find the range of the function s(t) = t^2 - 1 given the domain { -1, 0.5, 3.7 }

Question

Find the range of the function  s(t) = t^2 - 1   given the domain { -1, 0.5, 3.7 }

solomonzelman · Answer

You know that, $\color{#000000 }{ \displaystyle t^2  }$ is at least $\color{#000000 }{ \displaystyle 0  }$.
(i.e. $\color{#000000 }{ \displaystyle t^2\ge0  }$)

solomonzelman · Answer

You can subtract 1 from both sides and this will give you the domain.

1dfanatic · Answer

Im sorry i still don't get it

solomonzelman · Answer

Oh, my bad, you have the given ranges, I didn't see them.

solomonzelman · Answer

For any value in the domain, you need to plug in this value, to find the output.

solomonzelman · Answer

The inputs = domain,
The (corresponding) outputs = range.

solomonzelman · Answer

So, start from plugging $\color{#000000 }{ t=-1  }$,
into $\color{#000000 }{ \displaystyle s(t)=t^2-1 }$.

1dfanatic · Answer

I got (t+1)(t-1)...

solomonzelman · Answer

If  $\color{#000000 }{ \displaystyle t=-1 }$,  then  $\color{#000000 }{ \displaystyle s(-1)=(-1)^2-1 =1-1=0}$.

1dfanatic · Answer

I'm still so confused, sorry..