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Mathematics 19 Online
OpenStudy (anonymous):

Elimination help

OpenStudy (anonymous):

OpenStudy (kurayami95):

try to eliminate z .... so you have to...

OpenStudy (anonymous):

how do i eliminate z?

OpenStudy (anonymous):

subtract the third equation from the second

OpenStudy (kurayami95):

u most make into a negative tho

OpenStudy (anonymous):

can you guys right it out im so confused right now

OpenStudy (anonymous):

then subtract this new equation from the top equation and get rid of x then solve for the rest

OpenStudy (kurayami95):

im trying to xD

OpenStudy (kurayami95):

or maybe bill could explain better

OpenStudy (anonymous):

Thank you, I suck at math .

OpenStudy (anonymous):

i just need to see the equations

OpenStudy (anonymous):

okay: (3x+4y+2z)-(x+3y+2z)=0-1

OpenStudy (anonymous):

What does this give you?

OpenStudy (anonymous):

2x+y+z?

OpenStudy (anonymous):

the zs are eliminated (2z-2z=0)

OpenStudy (anonymous):

Whats next?

OpenStudy (anonymous):

subtract 2x from both sides to get y=-(2x+1)

OpenStudy (anonymous):

and then we would add?

OpenStudy (anonymous):

no now you substitute this value for y into all of the equations: 2x-2(2x+1)+z=-5 etc.

OpenStudy (anonymous):

where theres a y?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

what are these equations?

OpenStudy (anonymous):

2x-2(2x+1)+z=-5

OpenStudy (mazmaz):

https://www.khanacademy.org/math/algebra-basics/core-algebra-systems/core-algebra-systems-tutorial/v/solving-systems-of-equations-by-elimination The link above is to a video where there are two variables but he elimination step is the same I suggest you watch the other videos as well and go to youtube and search elimination I know how You feel I was once there with no hope. same type of question too

OpenStudy (anonymous):

2x-2(2x+1)+z=-5 3x-4(2x+1)+z=0 x-3(2x+1)+z=1

OpenStudy (anonymous):

just realized you only really needed the top equation. Here we have from the top equation: 2x-2(2x+1)+z=-5 -2x-2+z=-5 -2x+z=-3 z=-3+2x

OpenStudy (anonymous):

so we didnt need to add it to the three

OpenStudy (anonymous):

substitute this z value in for one of the equations and simplify

OpenStudy (anonymous):

only need to do that if you're using elimination

OpenStudy (anonymous):

which one? the second one?

OpenStudy (anonymous):

yeah I used the second equation

OpenStudy (anonymous):

once you get the x value you just plug that x-value into the equations we figured out for the other variables: y=-2x-1, z=-3+2x

OpenStudy (anonymous):

what do you get?

OpenStudy (anonymous):

y=x z=5x

OpenStudy (anonymous):

Can you show me your work when you substituted for the second equation? Did it start with: 3x+4(-2x-1)+2(-3+2x)

OpenStudy (anonymous):

oooooooh

OpenStudy (anonymous):

hold on

OpenStudy (anonymous):

i dont understand what to do here i add them?

OpenStudy (anonymous):

just simplify the equation and combine like terms

OpenStudy (anonymous):

how would i simplify?

OpenStudy (anonymous):

2x + 3x = 5x (3 + 5x + 2x2)

OpenStudy (anonymous):

?

OpenStudy (anonymous):

3x+4(-2x-1)+2(-3+2x) 3x-8x-4-6+4x -x-10=0 x=-10 y=19 z=-23

OpenStudy (anonymous):

now do you understand?

OpenStudy (anonymous):

i believe so. i still need more practice with all of this but you've helped me so much.

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