Question

@astrophysics

Answer 1

\(4x^{2/3} - 3x^{1/3} - 1 = 0\)

Answer 2

I have to find the solutions by factoring

Answer 3

I know so far it's going to be \((x^{1/3} ...)(x^{1/3}...)\), but that's it

Answer 4

Let x^(1/3)=y

Answer 5

Yes, shamim has the right idea :)

Answer 6

How would I do that? Put in x^(1/3) where?

Answer 7

U will get ur equation as
4y^2-3y-1=0
Right?

Answer 8

oohhh I see now

Answer 9

but there's not anything that multiplies to -1 and adds to -3...

Answer 10

Happy to help u

Answer 11

-3y=-4y+y
Right?

Answer 12

You can't do much with this anyways, \[(y-1)(4y+1)=0 \implies (x^{1/3}-1)(4x^{1/3}+1)=0\]

Answer 13

Does that make sense? We factored it normally, multiply 4 by -1 getting -4
then what two numbers add up to -3 and -4 which gives 1 and -4 then you can rewrite it as \[4y^2+y-4y-1=0\] yadi yadi yada

Answer 14

Where did -3 come from?

Answer 15

Ok let me slow down and use drawing I think this will help