Question

how do i solve 1/2(x-4)^2=8 by square rooting?

Answer 1

Do you mean (1/2)(x-4)^2=8? or do you mean 1 / [2(x-4)^2=8? which?

Answer 2

the first one

Answer 3

Thank you.

Please multiply both sides of this equation by 2 (for the purpose of getting rid of the fraction 1/2):\[\frac{ 1 }{ 2 }(x-4)^2=8\]

Answer 4

\[\frac{ 1 }{ 2 }(x-4)^2=8\]

Answer 5

Your result?

Answer 6

i already did those steps but im stuck at \[(x-4)^2 = \sqrt{16}\]

Answer 7

Where did the square root over the 16 come from? If you find the sqrt of the right side (16) of your equation, you must also find the sqrt of the left side.

Please show this as an equation.

Answer 8

i was doing it the way i was shown

Answer 9

after doing that, i got \[x -4 =\pm 4\]

Answer 10

is that correct?

Answer 11

sorry, but your \[(x-4)^2 = \sqrt{16}\]

Answer 12

is not correct. If you find the sqrt of 16, you must also find the sqrt of (x-4)^2 at the same time (not later on).

Answer 13

what is \[\sqrt{(x-4)^2}?\]

Answer 14

What is \[\sqrt{16}?\]

Answer 15

4

Answer 16

The set of answers comes from \[\sqrt{(x-4)^2}=\pm \sqrt{16}\]

Answer 17

Simplify the left side and set the new left side equal to \[\pm \sqrt{16}\]

Answer 18

i cant see the equations anymore

Answer 19

Simplify the following:\[\sqrt{(x-4)^2}=\pm \sqrt{16}\]

Answer 20

\[\sqrt{(x-4)^2}=\pm \sqrt{16}\]

Answer 21

What does the left side simplify to?

Answer 22

but i calculated and still got this

Answer 23

Yes, and on the right size you have \[\pm4\]

Answer 24

So, x-4 = plus or minus 4

Solve that for x, please (2 answers required)

Answer 25

so i was correct the first time but i was just missing the part where i square root (x-4)^2?

Answer 26

Looks that way. Please, would you finish the problem solution in the manner I've outlined above?