Question

ln(2x)=3^-x+2: solve for x

Answer 1

Can I help?

Answer 2

yes please

Answer 3

help please

Answer 4

i am here no screeming

Answer 5

can you help?

Answer 6

yes afcours

Answer 7

thanks

Answer 8

whait a second my cancalater glitching
bad writing right
becouse i am russian ahhaa

Answer 9

\[\ln (2x)=3^{-x+2}\]

Answer 10

that makes more sence

Answer 11

i dont understand it correctly i can do it only on 70%

Answer 12

i will call for help

Answer 13

@DanJS
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@rishavraj
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@Yttrium
@narissa
@MTALHAHASSAN2
@AloneS
@Kitten_is_back
@Empty

Answer 14

what this for ?

Answer 15

when you need help you call people like that

Answer 16

are they good ?

Answer 17

it says in there mail box some one called there name to help

Answer 18

yes they are experts

Answer 19

email them for help?

Answer 20

i did

Answer 21

just scroll around there name and you can see there points DanJS is my favirate one

Answer 22

ok , I will try

Answer 23

http://prntscr.com/9t90jc

Answer 24

here is one of them that i called

Answer 25

Lol... I'm doing Physics right now so I'm gone. :P :)

Answer 26

hi @jabez177

Answer 27

can you hep?

Answer 28

how me

Answer 29

any one can help

Answer 30

but he gave you the answere

Answer 31

who?, no one answer yes

Answer 32

the answere is 0 once again

Answer 33

no, the key is 1.78

Answer 34

hmm

Answer 35

ln(2x)=3^(-x+2) right?

Answer 36

right

Answer 37

where did you come from

Answer 38

this cant be solved algebraically, because you need equation to be all logs or all exponential not mixed

Answer 39

o ya i forgot i called you

Answer 40

I know that why hard to solve

Answer 41

haaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaahahahahah

Answer 42

inkyvoyd that is a strange que.......... Nancy

Answer 43

the answer is from using numerical approximation, im guessing newtons method which involves calculus

Answer 44

can you solve by step?

Answer 45

dumbcow is right here... it's too late at night for me to be doing mathematics.

Answer 46

ok, we will do tomorrow . thanks

Answer 47

i just woke up it is morning in russia

Answer 48

dumbcow you write slow

Answer 49

just in case

Answer 50

you were wondering

Answer 51

ok

\[x_n = x_{n-1} - \frac{f(x)}{f'(x)}\]
where
\[f(x) = \ln(2x) - 3^{2-x}\]
the derivative
\[f'(x) = \frac{1}{x} + \ln(3) 3^{2-x}\]

start with an initial value .... x_0 = 1
repeat until f(x) approaches 0

Answer 52

using an excel spreadsheet will make it easier and faster to compute all the iterations

Answer 53

http://www.wolframalpha.com/input/?i=ln%282x%29%3D3%5E%282-x%29
here the answer, I don't know how to solve step by step

Answer 54

thats what i was trying to do... you cant solve but you can approximate

i wrote out newtons method for approximating zeroes

Answer 55

thank

Answer 56

https://en.wikipedia.org/wiki/Newton%27s_method

Answer 57

thanks

Answer 58

thanks, i go sleep now I'm tired

Answer 59

haha ok your welcome