calculate R-thevenin

Question

curry · Answer

The answer i got was [jw / 2w] + [(1 + jw) /2]. Which can be simplified further, but is that right till there? i can simplify the rest... @ganeshie8

curry · Answer

Also, they wrote Z(iw)[Z(w)], but i'm not quite sure what that means.

ganeshie8 · Answer

that doesn't look correct

ganeshie8 · Answer

first work the equivalent reactance of inductor and resistor in parallel

ganeshie8 · Answer

2 || j*w*2

= ?

curry · Answer

capacitor and resistpr = [-2j/w + 2] / [-4j/2] = (1 + jw )
/2

curry · Answer

inductor and resistor = [2jw + 2 ] / [4jw] = (-8jw +8w^2)/(16w^2)

ganeshie8 · Answer

Looks your formula for parallel resistance is wrong

ganeshie8 · Answer

Correct formula : 

R1 || R2 = R1R2 / (R1 + R2)

ganeshie8 · Answer

you're using the wrong one : 

(R1+R2)/(R1R2)

curry · Answer

OO! -_- ...

curry · Answer

So is the equation [(8jw +8w^2)/(4+4w)] + [(-8jw+8)/(4w^2+4)]?

curry · Answer

so over all, i'm getting [8w^2 + 8]/[4w^2 + 4]. @ganeshie8, can you confirm this?