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OpenStudy (anonymous):
OpenStudy (michele_laino):
yes! I confirm that's right!
OpenStudy (anonymous):
thanks can you help me with more
OpenStudy (michele_laino):
ok!
OpenStudy (anonymous):
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OpenStudy (michele_laino):
here, the last option is correct, whereas the second option is wrong.
Please you have to search for the system which contains two equal equations
OpenStudy (anonymous):
what about a and c
OpenStudy (anonymous):
OpenStudy (michele_laino):
option a) is correct, also option d) is correct as I wrote before
option c) is wrong, since such system is composed by two different equations
OpenStudy (michele_laino):
the two equations are equivalent, namely the have the same solutions. If I divide both sides of the first equation by 2, I get:
\[\frac{{6x + 4y}}{2} = \frac{2}{2} \Rightarrow 3x + 2y = 1\]
namely I get the second equation
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OpenStudy (michele_laino):
so, what is the right option?
OpenStudy (michele_laino):
hint:
we can speak about coincident equations
OpenStudy (anonymous):
c
OpenStudy (michele_laino):
that's right!
OpenStudy (anonymous):
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OpenStudy (michele_laino):
here, as we can see, from the graph, we have one solution, furthermore the equations of the system are not coincident, so, you are right!
OpenStudy (anonymous):
:)
OpenStudy (michele_laino):
:)
OpenStudy (anonymous):
OpenStudy (michele_laino):
yes! I confirm the second option
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