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Mathematics 8 Online
OpenStudy (cheesecakekitten):

Which equation represents the graph?

OpenStudy (sparrow2):

which equation?

OpenStudy (cheesecakekitten):

A. f(x) = |x - 3| B. f(x) = |x + 3| C. f(x) = |x| - 3 D. f(x) = |x| + 3 I've narrowed it down to A or B.

OpenStudy (cheesecakekitten):

@priyar @Stormer15 Last question, it's just a bit trickier. I have other tests but hopefully those will be easy enough for me to do on my own.

OpenStudy (sparrow2):

it's a

OpenStudy (priyar):

see..if u substitute 3 in the equation for 'x' u must get y=0

OpenStudy (priyar):

so is it a or b ?

OpenStudy (sparrow2):

you can't always do that ,you should know how to graph

OpenStudy (cheesecakekitten):

Sparrow don't be rude.

OpenStudy (sparrow2):

what, i'm not being rude.. w teach you general principle how to solve any problem like this

OpenStudy (sparrow2):

ok i'm out

OpenStudy (priyar):

even while drawing the graph first we see where x or y takes zero value so as to make it easier to plot the graph..

OpenStudy (mathmale):

cheesecake: What is the "parent function" of the function whose graph is given here? How would you transform that function to obtain the given graph? Think in terms of horizontal and/or vertical transformations.

OpenStudy (priyar):

@CheesecakeKitten did u understand?

OpenStudy (mathmale):

Draw the graph of y=|x|. Next, suppose that we move this whole graph 2 units to the right. (Just an example). What would the graph now look like? apply this concept towards identifying which of the four choices of equation fits the given graph.

OpenStudy (priyar):

no..don't think like that..its simple..take your time to understand..

OpenStudy (priyar):

you are given an equation..y=|x-3|..so first simple step would be to check where the graph cuts the x-axis and y-axis..here what are those points?

OpenStudy (priyar):

@CheesecakeKitten ?

OpenStudy (cheesecakekitten):

Sorry I got lost in my own mind for a moment there. I PASSED! :D

OpenStudy (mathmale):

@CheesecakeKitten: OpenStudy says you are looking at someone else's post. Courtesy requires you to stay with your own post when others are trying to help you. Please become involved in the problem solution.

OpenStudy (priyar):

ok then..did u find those points?

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