Question

(2y^4)^-3
a.6y^12
b.-6/y^12
c.1/8y^12
d.-8/y^12
and please explain your answer

Answer 1

Expressing (2y^4)^-3 as\[(2y^4)^{-3}\]

Answer 2

... might make this problem clearer for you.

There are various rules for exponentiation, including the following:\[(x^a)^b=x ^{ab}\]

Answer 3

Please try applying this particular rule to the present situation.

Answer 4

thank you i think this will help

Answer 5

Hint: when you encounter a base with a negative exponent, what should you do to obtain an equivalent result with a positive exp?

Happy to be of help. Good luck!

Answer 6

thanks

Answer 7

thanks

Answer 8

thanks