Question

Which pair of numbers is relatively prime?


A.
10 and 33


B.
14 and 63


C.
26 and 91


D.
18 and 45

Answer 1

@Qwertty123

Answer 2

Ooo they gave you some tricky options :P
Not even a pair of even numbers lol
hmm

Answer 3

i honestly have no idea ;-;

Answer 4

Try to break the numbers down a little bit :)
14 = 7*2
63 = ?*?

Answer 5

idek what that means XD

Answer 6

We would like to rewrite each number as multiplication.
And see if any of the multiplication numbers match up :)

Answer 7

Example:
6 = 3*2
8 = 4*2

6 and 8 are NOT relatively prime, because they both have a 2 as a multiplier

Answer 8

14 = 7*2
63 = ?*?

what two numbers give you 63? :o

Answer 9

3 and 31 o-o
?

Answer 10

Hmm 3*31 = 93 woops :O

Answer 11

9 and 7

Answer 12

3 and 23

Answer 13

There is a nice divisibility trick for 3's and 9's.
If the digits add up to a multiple of 9, then it's divisible by 9.
6+3 = 9, so it's 9*something

and ya you spilled the beans -_- le sigh..

Answer 14

It would've been 3*21.
But then we have to break down the 21 further D:

So anyway,
14 = 7*2
63 = 7*9

They both have 7 as a factor/multiplier,
so they are NOT relatively prime.
So b is NOT the option we're looking for.

Answer 15

How bout option A?

10 = ?*?
33 = ?*?

Answer 16

isnt it c?

Answer 17

26 = 13*2
91 = 13*7

91 is a kind of difficult to break down, but it turns out they both have a 13 in them.

Answer 18

so its right?

Answer 19

if they share something...
then they are NOT relatively prime.
So no, it's not right

Answer 20

>-> crap

Answer 21

Try option A maybe,

Break down the 10 into factors,
and also the 33

Answer 22

5*2 and 3*11

Answer 23

?

Answer 24

Ok good :)
5*2
3*11

Oooo I think we did it!! ya?
The second set of numbers has no 5 or 2 in it,
and the first set of numbers has no 3 or 11 in it.

So they are relatively prime! :)

Answer 25

thanks so much