Mathematics
11 Online
OpenStudy (anonymous):
What is the major axis of the equation shown below? (x - 2)^2 / 49 + (y + 5)^2 / 36 = 1 Will give fans and medals.
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OpenStudy (misty1212):
Hi!!
OpenStudy (misty1212):
this is the standard form of a certain shape
do you know what it is?
OpenStudy (anonymous):
Sorry, I had forgotten to specify.
OpenStudy (misty1212):
i am asking if you know what it is
parabola
hyperbola
ellipse
OpenStudy (anonymous):
I think it's an ellipse. However, I would truly appreciate it if you would help me find the major axis.
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OpenStudy (misty1212):
yes it is an ellipse
OpenStudy (misty1212):
standard form is \[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\]
OpenStudy (misty1212):
where the center is \((h,k)\)
what is the center here?
OpenStudy (anonymous):
(2, -5)
OpenStudy (misty1212):
ok and next, which one is it?|dw:1453738335022:dw|
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OpenStudy (anonymous):
The one on the left.
OpenStudy (misty1212):
yes
OpenStudy (misty1212):
we know the center is \((2,-5)\) and \(a^2=49\) so \(a=7\) and \(b^2=36\) so \(b=6\)
what is left ?
OpenStudy (misty1212):
ooh the length of the major axis?
OpenStudy (anonymous):
Yes, please.
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OpenStudy (misty1212):
ok you are going to be annoyed at how easy this one is
we got \(a=7\) right?
OpenStudy (misty1212):
it is \(2a=14\)
OpenStudy (anonymous):
So, it's just 14?
OpenStudy (misty1212):
we can find the endpoints if you like but yes, it is just 14
OpenStudy (anonymous):
Man, that WAS easy. Thank you.
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OpenStudy (misty1212):
\[\color\magenta\heartsuit\]
OpenStudy (misty1212):
btw the length of the minor axis is .... 12
OpenStudy (anonymous):
Thank you for that too.