I am here to learn. I want to assist in anyway I can, but I am having difficulty completing this problem. Could someone possibly help me begin the process? Methane (CH4), ammonia (NH3), and oxygen can react to form hydrogen cyanide (HCN) and water according to this equation: 2CH4 + 2NH3 + 3O2 -- 2HCN + 6H2O How many grams of oxygen are required to produce 1 mole of H2O?

Question

I am here to learn. I want to assist in anyway I can, but I am having difficulty completing this problem. Could someone possibly help me begin the process? Methane (CH4), ammonia (NH3), and oxygen can react to form hydrogen cyanide (HCN) and water according to this equation: 2CH4 + 2NH3 + 3O2 --> 2HCN + 6H2O How many grams of oxygen are required to produce 1 mole of H2O?

yoongilife · Answer

Obviously this is a stoichiometry problem, but I am slightly unsure on how to being. Conversion? Mole ration?

photon336 · Answer

Ok first step is the full reaction balanced and how do you know?

yoongilife · Answer

Give me one moment to look over it, please.

yoongilife · Answer

Yes the equation is balanced. We know this through applying the law of conservation of mass.

photon336 · Answer

Alright great 

2CH4 + 2NH3 + 3O2 --> 2HCN + 6H2O 

now it's asking how many grams of oxygen are required to produce 1 mole of H2O.

yoongilife · Answer

This is where my confusion sets in. It asks how many GRAMS of oxygen are required to produce 1 MOLE of H2O. Should I use a conversion factor, or...?

photon336 · Answer

take a look at this. we multiply by the molar ratio of the two. that's why we need to balance the equation first and we set it up like this. 

$$?, O_{2}*\frac{ 6H2O }{ 3O2 } = 1 mol H_{2}O$$

sweetburger · Answer

2 ways of solving this the long way and the fast way I will write out both |dw:1453756428163:dw|
|dw:1453756593280:dw|

yoongilife · Answer

Ok, so we are trying to find the molar ratios between 3O2 AND 6H20.  The sources for these ratios are the coefficients of a balanced equation, right? So could we could compare 3O2 AND 6H20? I apologize I am trying to understand.

sweetburger · Answer

Yes your reasoning is correct the ratio is determined from the coefficients

sweetburger · Answer

I have class in about 25 minutes. I will be more than happy to answer questions when I get back. Sorry :/ I couldn't be more helpful right now...

yoongilife · Answer

That's fine, I am going to use the examples above to begin the process.

yoongilife · Answer

If you cross cancel and multiply/divide based on your first example wouldn't you get 16 g?

sweetburger · Answer

that appears to be correct yes but I didnt not spend as much time as i should have so I would need to check to make sure that value is correct