Question

{[Correct My Answers]} Two Of Them!

Answer 1

Solve the system by elimination.
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5
My answer:
A system of elimination requires to to add or subtract two equations together to eliminate a variable. Since you have three equations, you will want to bring that down to two equations with two variables. If you minus the second equation from the first equation: -2x+2y+3z=0 (-) -2x-y+z=-3 (=) 3y+2z=3 Now we want to create a second equation that only has the two variables y and z. We also want to create a second equation that is different from the first one. To do this we need to involve the 3rd equation. In this case we will add the first and the last equations together. -2x+2y+3z=0 (+) 2x+3y+3z=5 (=) 5y+6z=5 Now we have two equations to solve together by adding or subtracting. But in this case we will have to alter equation 2 (multiply all of it by 3) so that we can subtract one from 2. 3y+2z=3 (x3) 9y+6z=9 Now we can subtract. 5y+6z=5 (-) 9y+6z=9 (=) -4y=-4 y=1 Now that we have a value of y we can substitute that back into our equations to get other values. 3(1)+2z=3 3+2z=3 z=0 Now sub z=0 and y=1 back into equation 1. -2x+2(1)+3(0)=0 -2x+2=0 x=1

Answer 2

9.) Solve the system by substitution.
-x-y-z=-8
-4x+4y+5z=7
2x+2z=4
My answer: first isolate x in the third equation so 2x + 2z = 4 => 2x = -2z + 4 => x= -z + 2 then you can plug x into the first equation and reduce so -x -y -z = -8 => -(-z+2)-y-z=-8 => z-2-y-z=-8 => y=6 substitute x and y into the second equation so -4x+4y+5z=7 => -4(-z+2)+4(6)+5z=7 => 4z-8+24+5z=7 => 9z=-9 => z=-1 then you can substitute z into the third equation to find x 2x+2z=4 => 2x+2(-1)=4 => 2x-2=4 => 2x=6 => x=3 so x=3, y=6, and z=-1

Answer 3

I'm too lazy to read it all

Answer 4

weasel...then why bother replying?

Answer 5

Why not check your results in the ORIGINAL equations and then YOU tell US if the answer is correct?

Answer 6

@tkhunny ?? I don't see any problem with what I am doing. I have shown you directly how I have gotten my answers, lol what else do you guys want me to do to prove that I did it myself?

Answer 7

@tkhunny All I want is corrections here, there is no need for anything else. :)

Answer 8

@inkyvoyd I like your idea in making your pro pic the same color as the site...so you can be like a ghost.

Answer 9

...I think I may have left the first problem unsolved...whoops.

Answer 10

@inkyvoyd Are you correcting my work?

Answer 11

no sorry... honestly I got intimidated by the wall of text...

Answer 12

try breaking it into paragraphs and reposting.

Answer 13

Then correct the second one? Please

Answer 14

I'll correct both of them, if you make them less of an eyesore. Nobody wants to grade or correct that work.

Answer 15

Alright. I shall do it right now, hold a sec.

Answer 16

You have not completed the problem until you have verified your results. Go! Verify!!

Answer 17

9.) Solve the system by substitution.
-x-y-z=-8
-4x+4y+5z=7
2x+2z=4
My answer: x=3, y=6, and z=-1

Answer 18

@tkhunny I understand what you are saying, sir, but I don't have to do that for my dearest assignment.

Answer 19

Well, then how will you know if you have the correct result?

Answer 20

@tkhunny I don't really know how to correct them? Whoops

Answer 21

When your scoring mechanism says it's wrong, how will you know if you should go fight it?

Answer 22

@inkyvoyd Just correct this one,please
Solve the system by substitution.
-x-y-z=-8
-4x+4y+5z=7
2x+2z=4
My answer: x=3, y=6, and z=-1

Answer 23

-3-6-(-1) = -3-6+1=-9+1 = -8 -- Yup. The first one works.

Answer 24

Thank you.

Answer 25

You have to try the other two. It's a "simultaneous" solution. It's easy to make ONE work.