exponential growth
how many years from 1971 to 2015?
294,105(8.5)^44?
no
the 44 is right
to increase a number by \(8.5\%\) multiply it by \[100\%+8.5\%=108.5\%=1.085\]
to do it 44 times, compute \[294,105\times (1.085)^{44}\]
@satellite73 whats the final answer?
idk i didn't compute that number, i am sure you can do it
3802.750036629138
that what i get
i get something much much bigger
4096.75003663
also it says "round to the nearest whole number "
so 1.1?
@satellite73 im lost bro
the answer is written in scientific notation
bro i been waiting here lol =(
1.06515028525982306079399906161498607122884440956219587769... × 10^7
1.06515
move the decimal seven places
\[10,651,502\]
10.7?
@mathmale help bro
i wrote the answer above the wolfram link gave it to you in scientific notation the \(10^7\) at the end meant move the decimal seven places to the right
dont use wolf then use mathpapa
Please step back and review what you've done here. This problem involves exponential growth over a 44-year period. If you go further in math you will encounter exponential growth repeatedly, so it's worth learning the ropes. You begin (in 1971) with 294105 female participants. That number increases by 8.5% per year, over 44 years. That's a LOT of growth. What have you learned from working on this problem? Again, expect to see this material in the future.
10,651,502
Right. But that doesn't answer my question (above).
294,105*(1.085)^44
Yes, that's how you'd estimate the population after 44 years.
That's an "exponential growth equation."
3802.750036629138
@mathmale
What was the reason that you abandoned your first answer (10,651,502) and adopted the much smaller 3802.75 in its place? I need to understand y our reasoning. Are we in agreement that the number of female sports participants is growing rapidly? If so, which answer makes more sense (if we begin with 294105): 10651502 or 3803?
i dont know bro
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