if f(x) = x+2 and g(x) = 3x find f(x)/G(x)
You're just dividing, \[\frac{ f(x) }{ g(x) } = \frac{ x+2 }{ 3x }\] does that make sense?
lol yeah, you are not even really dividing just put one on top of the other
Haha yeah xD
so I'm basically just switching the numbers around lol ? how do I know which order to go in though ?
Naw you're not even dividing as sat has pointed out, notice you want \[\frac{ f(x) }{ g(x) }\] so you're basically substituting the values \[f(x) = x+2\] and \[g(x) = 3x\] so putting it together \[\frac{ f(x) }{ g(x) } \implies \frac{ x+2 }{ 3x }\]we have
Ok I get it a little bit more now that I can see is this problem basically the same thing If f(x) = 3x + 5 and g(x) = 2x - 9, find f(x) - g(x). 5x + 4 x - 4 x + 14 5x - 4
Yeah, but you'll have to simplify this one once you plug it in
So how would this one look?
the answer would be 5x - 4 because 3x + 2x = 5x and 5 - 9 equals -4 equaling 5x - 4
\[f(x)-g(x) = 3x+5-(2x-9)\] we must be careful
Note the brackets
ok so I was wrong ? and I know I always forget to use the brackets .
Yeah because we are subtracting by all of g(x) so we must distribute the negative over 2x and -9 so we get \[f(x)-g(x) = 3x+5-(2x-9) = 3x+5-2x+9\]
Now simplify and you're done
so 5x - 4 would be my answer ? or x + 14 ?
3x-2x = x 5+9 = 14 So we have x+14
The inverse of f(x) = x + 2 is f-1(x) = 2x − 4. TRUE FALSE I'm sorry if I'm asking to many questions
To find the inverse: Replace f(x) with y Switch x's and y's, so put x where y is and y where x is. Solve for y Replace y with f^-1(x)
so it would look like x= y + 2 is f - (y) = 2y - 4 ?
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