how do you write the ground state electron configuration for H2+, He2+ and He2^2+ and what is the bond order for each one?

Question

anonymous · Answer

@Photon336

anonymous · Answer

i got the bond order for H2+ to be 1/2 and the bond order for He2+ to be 1/2

anonymous · Answer

@xapproachesinfinity

anonymous · Answer

the only thing i have left to find is the ground state configuration of He2^2+ and its bond length

photon336 · Answer

Helium has two electrons right?

photon336 · Answer

so the +2 charge means that both its electrons are gone and there are two protons.

anonymous · Answer

right but how does that affect the ground state electron configuration and bond order?

photon336 · Answer

well, if we're talking about that ion. it has no electrons .

anonymous · Answer

so it doesnt have any configuration or bond order?

anonymous · Answer

Bond order = [(Number of electrons in bonding molecules) - (Number of electrons in antibonding molecules)]/2

photon336 · Answer

I see, well for helium 2+ I think it would be zero

anonymous · Answer

thats what i thought it was but is there any way to find the configuration

photon336 · Answer

$$1s^0$$

anonymous · Answer

thank you do you mind if i ask one last question?

photon336 · Answer

yeah, I have a couple of minutes to spare

anonymous · Answer

do you want me to create another question or just ask it here

photon336 · Answer

can ask it here

anonymous · Answer

ok thank you

anonymous · Answer

i just had to rank the order of increasing bond lengths of H2+, H2, He2+, He2^2+ and H2-

photon336 · Answer

show us what you have

anonymous · Answer

i only know the bond length of H2 to be 75

anonymous · Answer

not sure if that is right either

photon336 · Answer

bond length and bond order are two different things I think

anonymous · Answer

yes these are bond length

photon336 · Answer

jUST on a side note take a look @ the molecular orbitals for H2- 


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