Question

A system of equations is shown below:
5x - 5y = 10
3x - 2y = 2

Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this.

Part B: Show that the equivalent system has the same solution as the original system of equations.

Answer 1

@mathmath333

Answer 2

@TrojanPoem

Answer 3

Can you help?

Answer 4

@Opcode

Answer 5

The questions asks you to take the any of the given equations for ex :
3x - 2y = 2

get a multiple of it

and sum it to 5x - 5y = 10

Answer 6

so take

3x - 2y = 2 ( * 2)

6x - 4y = 4

+ 5x - 5y = 10

11x - 9 y = 14


new system of equations is

11x - 9y = 14

5x - 5y = 10

Answer 7

A multiple of what number?

Answer 8

I fairly confused.

Answer 9

Any number 2 , 3, 4, 100000

Answer 10

zero -> will destroy your equation
1 -> won't matter

Answer 11

So,

(3x - 2y = 2)*2

6x - 4y = 4

Is that what I should write.

Answer 12

No it says
Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other

you got a multiple of the other (6x - 4y = 4)

now it asks for the sum of that multiple (6x - 4y = 4) and the other equation ( 5x - 5y = 10)

Answer 13

So,

(3x - 2y = 2)*2

6x - 4y = 4

6x - 4y = 4 + 5x - 5y = 10

11x - 9y = 14
5x - 5y = 10


^ Is that what I should write?

Answer 14

@TrojanPoem

Answer 15

@Kainui

Answer 16

@Somy

Answer 17

@tHe_FiZiCx99

Answer 18

@Opcode

Answer 19

@Lovelarap

Answer 20

@hartnn

Answer 21

yeah

Answer 22

(3x - 2y = 2)*2

6x - 4y = 4

6x - 4y = 4 + 5x - 5y = 10

11x - 9y = 14
5x - 5y = 10

this is correct for A

Answer 23

Now I need to solve for x and y? Correct"?

Answer 24

if i'm not wrong yes

Answer 25

Ok thanks everyone!