A company has 200 machines. Each machine has 12% probability of not working
If you were to pick 40 machines randomly, the probability that 5 would not be working is
the probability that all would be working is
and the probability that at least one machine would be working is
@mathmale @Mashy @magepker728 @magicremix123
@Willie579
@agent0smith
nit sure abt this i'm afraid I think it might be a Binomial Distribution.
I agree: binomial distribution. Look this up and refresh your memory of what a "binomial distribution" involves. How large is the sample (n)? What is the probability (p) that a given machine would not be working? How would you express "the binomial probability that 5 machines out of 40 would not be working?"
12.5% is equal to five out of fourty @welshfella
More specific hints: 1) n=40 (there are 40 samples) 2) p=0.12 (probability that a given sample will be defective) 3) How would you evaluate a binomial probability? Some calculators have built-in statistical utilities; the TI-84 has several, including binomial probability: binompdf(n,p) There's a formula for this purpose; look up "binomial probability" on the 'Net You could calculate the prob. that exactly 3 machines out of 40 would not be working; or you could find the prob. that "at least 2 are not working." I encourage you to do a bit of research and then come back with some work of your own to discuss, or at least questions about what to do and how to do it.
ok
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