Question

Boolean algebra

' = not
+ = or
* = and

a+b'+a'b+c'

Answer 1

how do I simplify this? it should become 1

Answer 2

i dont understand theres no numbers

Answer 3

This is Boolean algebra, the variables can only be 0 or 1 and its for electric circuits @elite

Answer 4

oh ok i see

Answer 5

I think this is the XOR definition
\[A \oplus B = \overline A ·B +A·\overline B\]

Answer 6

a+b'+a'b+c' > using consensus law for the sum a + a'b > a+ a'b+b > then the absorb law so that a'b + b = b > so we have a + b' + b + c' > where b'+b=1 > so we have 1 + a + c' and then I add (c' + c) which equals to 1 but we use the distributive law and gets c' + c + ac' + ac + c' + 1

c'+ c = 1, c' + 1 = 1
1 + 1 = 1

so we have 1 + a(c'+c) => 1 + a = 1

Answer 7

@ParthKohli could you just check to see if im doing right?

Answer 8

from->\[A+\overline B+\overline A B+\overline C\]
De morgan:
\[A+B=\overline {\overline A·\overline B}\ ,\ \ \ ->\ \ \ A + \overline B=\overline {\overline A·B}\]
\[\overline {\overline A ·B}+\overline A ·B+\overline C=\]
\[=\overline Z +Z +\overline C \]
\[= \overline C\]
note : (Z'+Z) = 1. I Just work in the first pair of terms

Answer 9

ouch =1