Question

Will fan and medal

Simplify the expression

2u^2v^2
--------
22u

I know it's
1
-----
11

Answer 1

\[\frac{ 2u^{2}2v^{2} }{ 22u }\]

Answer 2

let me ask you @WhatEven based on the problem we did before, how would you go about answering this?

Answer 3

Before I would have taken it so the top read \[1uv^2\]

Answer 4

(There is no 2 infront of the v)

Answer 5

great

Answer 6

what about the bottom

Answer 7

But I know that that's incorrect so now I feel like it would stay the same.

Answer 8

because both terms are multiplied by 2 in the numerator we can factor out a 2 right?

take a look here.

\[\frac{ 2u^{2}2v^{2} }{ 22u } = \frac{ 2(u^{2}v^{2}) }{ 22u }\]

Answer 9

you already know that we can further simplify this to

\[\frac{ u^{2}v^{2} }{ 11u }\]

but we're not done yet. we can simplify this yet again can you see why?

Answer 10

@WhatEven

Answer 11

Uhmmm \[\frac{ uv^2 }{11 }\]

Answer 12

what's your justification?

Answer 13

you subtract the bottom u from the top one

Answer 14

exactly