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OpenStudy (anonymous):
What is the pH of a 0.01 M benzoic acid solution?
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OpenStudy (abb0t):
pH = - log[H\(^+\)] The units for [H\(^+\)] are in M which is mol/L
OpenStudy (jfraser):
the Ka for benzoic acid is \(6.3*10^{-5}\). Use an ICE table approach
OpenStudy (abb0t):
ICE tables are so confusing. Just set up the K\(\sf _a\) equation.
OpenStudy (jfraser):
@abb0t sometimes true, but the KA equation is just the end result of the ICE table
OpenStudy (anonymous):
Benzoic acid is a weak acid. I have used a weak acid pH calculator. The answer is found to be pH = 3.12 The pH calculator link: http://chem-net.blogspot.com/search?q=weak+acid+calculator
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