TRIGNOMETRY
If A and B are acute positive angles satisfying the equation 3 sin2 A + 2 sin2B = 1 and 3 sin 2A – 2 sin2B = 0, then find the value of (A + 2B).

Question

TRIGNOMETRY
If A and B are acute positive angles satisfying the equation 3 sin2 A + 2 sin2B = 1 and 3 sin 2A – 2 sin2B = 0, then find the value of (A + 2B).

welshfella · Answer

are all these double angles? 2A ad 2B?

anonymous · Answer

YES

anonymous · Answer

IN THE FIRST EQUATION THIS IS SQUARE'S NOT DOUBLE ANGLES

anonymous · Answer

3 sin^2 A +2sin^2 B = 1

welshfella · Answer

right - i was'nt sure about that.

anonymous · Answer

I THINK YOU NEED THESE EQUATIONS AGAIN

anonymous · Answer

3 sin^2 (A) + 2 sin^2(B) = 1 and 3 sin 2A – 2 sin2B = 0,

anonymous · Answer

I THINK THIS TIME IT'S MORE CLEAR

anonymous · Answer

IS IT

welshfella · Answer

yes

anonymous · Answer

PLEASE SOLve and give me the whole,understand able solution

anonymous · Answer

i give you medal;

welshfella · Answer

i would help you but at the moment I can't see a way to do this.

welshfella · Answer

No sorry I cant think of a way to do this one.

welshfella · Answer

I'LL TRY IT OM WOLFRAMAPLHA

welshfella · Answer

http://www.wolframalpha.com/input/?i=3+sin^2+A+%2B+2+sin^2+B+%3D+1%2C+1+%2B+3+sin+2A+-+2+sin+2B+%3D+0+Solve+the+system That is Complex!!!! I think there might be an error in your question

welshfella · Answer

though I tried entering the criteria that angles nust be acute and positive and 'find A + 2B' but it ignored it.

sparrow2 · Answer

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