Question

Consider the following reaction in a closed system:
(equation is in the comment section)
Which of the following will decrease the rate of the forward reaction?

A) Add so H2
B) Remove some HI
C)increase the volume
D)Increase the temperature

Answer 1

\[H _{2}\left( g \right)+I _{2}(g)\rightarrow 2HI \left( g \right)\]

Answer 2

@sweetburger mind helpin with one more

Answer 3

Although I dont know the enthalpy for this reaction I will assume it is negative as two individual diatomic elements are combining to form a compound thus hopefully becoming more stable? Not sure. What I do know is that If you add H2 you are increasing a reactant therefore this will drive the reaction forward. If you remove HI you are decreasing the equilibrium amount of products so the reaction will be driven forward to reestablish equilibrium. If you increase the volume there will be no affect on the given reaction. This is because the number of gaseous reactants is the same as the number of gaseous products.

Answer 4

This leaves us with what I assume a -Delta H so the Energy will count as a product. If you increase the temperature you will effectively increase the amount of products which will increase the rate of the reverse reaction to drive the extra product to reactant to reestablish equilibrium.

Answer 5

so if they all increase it the witch one decreases

Answer 6

so im guessing its C?

Answer 7

No they dont all increase it.

Answer 8

Changing volume does actually nothing to this particular reaction.

Answer 9

I think you misread that I stated that the higher temperature will increase the rate of the reverse reaction not the forward reaction. Therefor its effectively "lowering the rate of the forward reaction."

Answer 10

ohhh okay lol yeah i misread

Answer 11

so its increase temperature?

Answer 12

yes

Answer 13

i put that in and it told me C was the right answer? *confused*

Answer 14

https://www.chem.tamu.edu/class/majors/tutorialnotefiles/lechatelier.htm

Answer 15

If the moles of gas reactants is equal to the moles of gas products, a change in pressure will have NO EFFECT on the equilibrium. Therefore the forward reaction rate will not be increased.

Answer 16

hmmmm