Question

please need help in finding k for parallel and perpendicular lines

Answer 1

Ill try

Answer 2

here is the questions. :))

Answer 3

Okay give me one minute

Answer 4

i already solved no.1 letter a and b but not sure though.

Answer 5

@dumbcow

Answer 6

not too sure about this one sorry :) im sure that dumbcow can solve this.

Answer 7

ohh okaay but thankyou anyways. @imsleeziboii

Answer 8

first convert each equation into slope-intercept form
---> y = mx+b , where "m" is the slope

parallel lines have equal slope
perpendicular lines have slopes that have a product of -1 (m1*m2 = -1)

Answer 9

after this i'll just equate the two k's together?..
and so basically in 1. (a) the answer is k= 1/2? is this correct?

Answer 10

liten if these lines are parralel their slopes are equal ,try to convert them in standard form as
y=mx+c and compare the m and you will found your answer

Answer 11

ohh okaay2. thankyou

Answer 12

yes k = 1/2 for part a

Answer 13

these are the very easy questions

Answer 14

for part b) you should get
\[\frac{2-k}{3} = k+1\]
when you equate the slopes

Answer 15

and in no. 1 part b. its -1/4

Answer 16

okaay i'll try to solve no.2 can you check them after? thank you so much

Answer 17

correct on part b

sure thing

Answer 18

in no.2 part a.. the k=1/2 also?

Answer 19

correct

Answer 20

okaay but im having problems in solving the part b

Answer 21

in the first equation it's y=k^2x +1 and y=\[\frac{ x }{ k-2 }\] +4

Answer 22

is te 2nd.. what should i do then?

Answer 23

multiply 2 slopes, set equal to -1
\[k^2 * \frac{1}{k-2} = -1\]
\[k^2 = -(k-2)\]
\[k^2 +k -2 = 0\]

Answer 24

ohhh soo (k+2) (k-1)
with k=-2 and k=1 both will be the answers?

Answer 25

yep you got it

Answer 26

yeaay! aaww thankyouu so much for your time and effort @dumbcow :))

Answer 27

your welcome