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How to find the derivative of @dan815 @hartnn @freckles
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\(\large g(x)=\Large\sqrt{\frac{x+3}{2}}\)
the denominator \(\sqrt 2\) is a constant, you can bring that out. just try to get the derivative of \(\sqrt{x+3}\)
Oh, okay. So would I change it to \(\Large (x+3)^{1/2}\)
And use the chain formula?
yes, now you'll have to use the chain rule, and the fact that \(\Large (x^n)' = n x^{n-1}\)
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So, would it be \(\Large\frac{1}{2\sqrt{x+3}}\)
right and finally put the \(\sqrt 2\) in the denominator
Okay, so then \(\Large\frac{1}{2\sqrt{2x+6}}\)
right or \(\Large\frac{1}{2\sqrt{2(x+3)}}\)
Is there a preferred way?
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whatever you feel is more simplified
Okay, thank you
welcome ^_^
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