Solve the following inequality and then choose the correct solution. -\frac{x}{9}\; -\; 2< 3 A. x> -\frac{5}{9} B. x> -45 C. x< -45 D. x< -\frac{5}{9}
\[ -\frac{x}{9}\; -\; 2< 3\]
\[A. x> -\frac{5}{9}\]
@sleepyjess
Where is your work?
Inequalities! I'm doing this right now in my class! Let's isolate x
I don't even know how to even do this, so I can'y show my work :P
I'll let Jess take over if she wants to :)
Ok, we need to isolate X. What do fractions have to do with inequalities though? They are very confusing :\
zeron, do you know how to solve \(-\dfrac x9 -2 = 3\)
Nope
I know how to it with no fractions, or is that even a fraction? 9x - 2 = 3? Add 2 and divide by?
Okay. Let's work with what you know. Add 2
2 is negative so that cancels out. 3+2=5 9+2=11
That gives \(-\dfrac x9 > 5\). Now, we added to get rid of subtraction. You know we divide to get rid of multiplication. So what do you think we do to get rid of division?
Multiply by 9?
Almost, look at the sign, 9 is negative, so multiply by -9
ohh. If we multipled 9 by a positive, would the outcome be negative or posiitve?
If we do \(-\dfrac x9 * -\dfrac 91\), the -9 in the denominator of the first fraction cancels with the -9 in the numerator of the second fraction
Oh so there is no longer a 9. just X
Correct, now 5*-9 =?
45.
-45*
If we multiply negative by a positive we get negative, right?
Correct, now, when we have an inequality and we have to multiply or divide by a NEGATIVE number, in this case -9, we have to flip the inequality sign. So \(x>-45\) actually becomes \(x < -45\)
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