y=-24/x^2+8

a)all real numbers greater than or equal to -3 or less than 0
b) all real numbers
c)all real numbers greater than or equal to -3
d)all real numbers less than 0

Question

y=-24/x^2+8 

a)all real numbers greater than or equal to -3 or less than 0 
b) all real numbers 
c)all real numbers greater than or equal to -3 
d)all real numbers less than 0

ohmybookness · Answer

which of these correctly describes the RANGE of the function.

ohmybookness · Answer

@RhondaSommer

ohmybookness · Answer

@pooja195

ohmybookness · Answer

@jhonyy9

jhonyy9 · Answer

what mean ,,range" of a function ?

ohmybookness · Answer

sadly, I'm trying to figure that out also

jdoe0001 · Answer

$\bf y=\cfrac{-24}{x^2+8}\qquad or \qquad y=\cfrac{-24}{x^2}+8?$

ohmybookness · Answer

It's the first equation
that you did.

y=-24
    ----
   x^2+8

jdoe0001 · Answer

well... .think about it

is a rational function
meaning, the only time "y" doesn't have a value
is when the fraction is "undefined"
when does that happen?  well, when the denominator is 0

so.... at what value for "x", will make the denominator 0?

notice, you have $x^2+8$  so, to get a 0, $x^2$  must turn into a -8
so $x^2-8 \implies -8+8 \implies 0$

jdoe0001 · Answer

so... at what value of "x", can $\bf x^2 = -8$  so it zeros out with the +8?

ohmybookness · Answer

2?