Will give a medal
which pair of equations, when graphed, has lines that are perpendicular. y=2x-7 , x+3y=3 5x-8y=9 , 12x -5y=7 3x+6y+8 , y=3x-8 2y=-3x+5 , 2x-3y=4
Desmos graphing calculator should help! xD
if the product of their slope is -1 , it means they r perpendicular
How do I know if the produce is -1
multiply the slopes
y = mx + c m - slope
For now your best bet may be finding the slope of each equation in each pair. Each pair yields 2 slopes. Take the slopes and multiply them together. If the product is -1, then you've found the pair of graphs that are perpendicular to each other.
If this condition is met, we say that the slope of one line is the negative reciprocal of the slope of the other.
so let's say i just pick one of the four choices, i plug in (-1) wherever i see a x?
Sorry, but no. Suppose you pick the last of the four choices. Find the slope of each line (there will be two). Multiply these slopes together. If the product is -1, then the 2 lines are perpend. If the product is not -1, the lines are not perpendicular. Try this. I need to get off the 'Net, but will be back on later. Good luck and thank you for asking questions for clarification.
and Thankyou for your help @mathmale
@DuranK can you help me through this? Im not good with slope
do you know how to find slope?
y=mx+b
right just find the slope for each one and you'll get your answer (: id help more but i have to go
thanks @DuranK
no problem
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