Question

Help with a few questions please? #QuickHelp #willMEDALandFAN !!

Answer 1

@satellite73 lend a hand?

Answer 2

\[b^x=y\iff \log_b(y)=x\]

Answer 3

for example \[5^2=25\iff \log_5(25)=2\] you should know how to swtich back and forth quiclkly
\[\log_10(.01)=-2\iff 10^{-2}=0.01\]

Answer 4

i made a typo there \[\log_{10}(0.01)=-2\iff 10^{-2}=0.001\]

Answer 5

So what do you think It would be? Im assuming from what you just said, It'd be C

Answer 6

no not C

Answer 7

\[\left(\frac{1}{3}\right)^3=\frac{1}{27}\] the base is \(\frac{1}{3}\) that should be the base of your log

Answer 8

okay its B then, correct?

Answer 9

nope

Answer 10

Wow.. So im guessing the only option now is A.

Answer 11

\[\huge \log_b(\color{red}A)=\color{blue}B\iff b^{\color{blue}B}=\color{red}A\]

Answer 12

Ok.. Lets move onto the next one?

Answer 13

yeah first one i sA

Answer 14

second one is the same, only you are going in the other direction

Answer 15

lag is real bad here
make a guess, i will check it

Answer 16

lol take me through the steps

Answer 17

And yeah the lag on this website period is terrible

Answer 18

\[\huge \log_b(\color{red}A)=\color{blue}B\iff b^{\color{blue}B}=\color{red}A\]
\[\huge \log_2(\color{red}{128})=\color{blue}7\iff b^{\color{blue}B}=\color{red}A\] fill it in

Answer 19

It's D. 128=2^7

Answer 20

yes

Answer 21

Lets move onto the next one

Answer 22

again, fill it in

Answer 23

1/9 = 3^-2

Answer 24

\[\huge \log_b(\color{red}A)=\color{blue}B\iff b^{\color{blue}B}=\color{red}A\]\[\huge \log_3(\color{red}{\frac{1}{9}})=\color{blue}{-2}\iff b^{\color{blue}B}=\color{red}A\]

Answer 25

yes

Answer 26

you getting this? (i hope)

Answer 27

Yes kinda lol Was I correct for my last answer^^?

Answer 28

yes

Answer 29

last one answer this question : 2 to what power is 16?

Answer 30

2^4

Answer 31

\[\huge \log_b(\color{red}A)=\color{blue}B\iff b^{\color{blue}B}=\color{red}A\]\[\huge \log_2(\color{red}{16})=\color{blue}4\iff 2^{\color{blue}4}=\color{red}{16}\]

Answer 32

Can you help with a few more please?

Answer 33

sure
this lag is really killngme though

Answer 34

laggy*

Answer 35

a) 49 to what power is 7?
if that is not obvious, say so and i will show you
that is what you are looking for

Answer 36

Its not obvious lol

Answer 37

\[\sqrt{49}=7\] which can be written as \[49^{\frac{1}{2}}=7\] you have to think of all of these in terms of exponents

Answer 38

since \[49^{\frac{1}{2}}=7\] that is the same as \[\log_{49}(7)=\frac{1}{2}\]

Answer 39

b) cannot be solved, you cannot take the log of a negative number

Answer 40

Ok we've finished two fast lol next one please

Answer 41

5 to what power is 1?\[5^x=1\] what is \(x\)?

Answer 42

0

Answer 43

bingo
so \[\log_5(1)=0\]

Answer 44

Ok lets move onto the last two

Answer 45

they have nothing to do with logs, true for any function \(f\)
compared to the graph of \(y=f(x)\) the graph of \(y=f(x+1)\) is translated LEFT 1 unit

Answer 46

oh hold on
it is a bit ambiguous

Answer 47

not sure if they meant \[\log(x+1)\] or \[\log(x)+1\]

Answer 48

because they are lazy and don't use parentheses
where does this question come from?

Answer 49

From a practice

Answer 50

it is not clear so lets go to the last one
ask your lazy teacher if they meant \[\log_5(x)+1\] which is UP 1 or \(\log_5(x+1)\) which is LEFT 1

Answer 51

Gotcha lol

Answer 52

Lets do the last one

Answer 53

ima just tel you
compared to \(y=f(x)\) the graph of \(y=f(x-5)+3\) is
RIGHT 5, UP 3

Answer 54

THANKS! i appreciate it lol & can you atleast fan me back?

Answer 55

sure, i'll send you an invoice

Answer 56

just kidding, i fanned you

Answer 57

lol I didn't get a notification but ill take your word for it. Thanks though!

Answer 58

you can check by sending me a message
i only get them form people i am a fan of