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OpenStudy (anonymous):
sorry wrong attachment hold on
OpenStudy (anonymous):
OpenStudy (astrophysics):
Ok lets break it down, c = child tickets, and a = adult tickets
So it says each child ticket for a ride costs $3 and each adult ticket costs $5
So we have \[3c+5a=115\] where 115 is $115 (collected total) good so far?
OpenStudy (astrophysics):
That will be our equation for price of tickets, next we need to figure out how many tickets were sold, which should be a simple equation, can you figure it out :)
OpenStudy (anonymous):
it's b
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OpenStudy (astrophysics):
Yes!
OpenStudy (anonymous):
I have a few more. Is it okay?
OpenStudy (anonymous):
OpenStudy (anonymous):
@Astrophysics
OpenStudy (astrophysics):
Can you use the similar idea as before to set up the equations
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OpenStudy (anonymous):
it's a
OpenStudy (anonymous):
@Astrophysics
OpenStudy (astrophysics):
Can you show your work please
OpenStudy (anonymous):
hold on it's gonna take a while
OpenStudy (astrophysics):
Take your time :)
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OpenStudy (anonymous):
If the ride collected a total of $148, and 38 tickets were sold,
i thought how many of each were sold?
so I just let c be the total of children tickets and a the number of adult's tickets.
a + c = 38
6a + 2c = 148
18 adult and 20 tickets.
OpenStudy (anonymous):
I tried using the similar steps like you said @Astrophysics