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Mathematics 10 Online
OpenStudy (anonymous):

@astrophysics

OpenStudy (anonymous):

sorry wrong attachment hold on

OpenStudy (anonymous):

OpenStudy (astrophysics):

Ok lets break it down, c = child tickets, and a = adult tickets So it says each child ticket for a ride costs $3 and each adult ticket costs $5 So we have \[3c+5a=115\] where 115 is $115 (collected total) good so far?

OpenStudy (astrophysics):

That will be our equation for price of tickets, next we need to figure out how many tickets were sold, which should be a simple equation, can you figure it out :)

OpenStudy (anonymous):

it's b

OpenStudy (astrophysics):

Yes!

OpenStudy (anonymous):

I have a few more. Is it okay?

OpenStudy (anonymous):

OpenStudy (anonymous):

@Astrophysics

OpenStudy (astrophysics):

Can you use the similar idea as before to set up the equations

OpenStudy (anonymous):

it's a

OpenStudy (anonymous):

@Astrophysics

OpenStudy (astrophysics):

Can you show your work please

OpenStudy (anonymous):

hold on it's gonna take a while

OpenStudy (astrophysics):

Take your time :)

OpenStudy (anonymous):

If the ride collected a total of $148, and 38 tickets were sold, i thought how many of each were sold? so I just let c be the total of children tickets and a the number of adult's tickets. a + c = 38 6a + 2c = 148 18 adult and 20 tickets.

OpenStudy (anonymous):

I tried using the similar steps like you said @Astrophysics

OpenStudy (anonymous):

OpenStudy (anonymous):

@Astrophysics are you there

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