Question

A straight line intersects the same branch of general hyperbola in P1 and P2 and meets its asymptotes in Q1 and Q2 .Then P1Q2-P2Q1 is equal to....

Answer 1

@hartnn @parthkohli pls...do help..

Answer 2

just because of the nature of the information provided in the problem, i would say the answer is zero. lol

Answer 3

How?

Answer 4

Because of symmetry it's obvious for any vertical line. But let's solve it in a proper manner. Asymptotes:\[x^2/a^2 - y^2/b^2 = 0\]Hyperbola\[x^2/a^2 - y^2/b^2 = 1\]

Answer 5

Then....

Answer 6

Then take \(y= mx+c\) and solve.

Answer 7

Not recommended though

Answer 8

But it's really obvious for vertical lines because of symmetry about axes.

Answer 9

What about any general line ??

Answer 10

sorry i'll be away for a while

Answer 11

It's alryt....

Answer 12

Hi still need help or are you being helped??

Answer 13

No, i need help....

Answer 14

I have to agree with @ParthKholi

Answer 15

Can't we do it assuming general line

Answer 16

The answer is zero I got it also

Answer 17

U also assumed vertical line only....

Answer 18

yes

Answer 19

Bt y not other line

Answer 20

Brb

Answer 21

Ok...

Answer 22

Ok....Back

Answer 23

Yaa so now would you tell me why not in generalized way?

Answer 24

Oh that's hard and im not used to doing it in a not generalized way but I will try.......

Answer 25

Yup...surely....

Answer 26

hmmmmmm