Question

Find the exact solution to the equation.
5^(6-2x)=25
I know I need to use log, but can I have help with setting up the solution?

Answer 1

You can either use logs or just compare the exponents,

1. Using log:
\(\Large 5^{6-2x} = 25 \\ \log 5^{6-2x} = \log 5^2 \\ (6-2x)\log 5 =2 \log 5 \\ 6-2x = 2\\ ... \)

2. just compare the exponents,
\(\Large 5^{6-2x} = 25 \\\Large 5^{6-2x} = 5^2 \\ \implies 6-2x =2 \\ ...\)

Answer 2

that is if you still needed help :)

Answer 3

thank you.