Mathematics
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OpenStudy (shaleiah):
@Michele_Laino
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OpenStudy (michele_laino):
we have to compute the area of the base triangle
OpenStudy (michele_laino):
as first step, of course
OpenStudy (michele_laino):
the volume is not 96 cm^3
OpenStudy (shaleiah):
Alright, what formula should I apply?
OpenStudy (michele_laino):
here it is:
\[\Large volume = \left( {base\;area} \right) \times height\]
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OpenStudy (michele_laino):
|dw:1454017741013:dw|
base area= \((6 \times 8)/2=...?\)
OpenStudy (shaleiah):
24
OpenStudy (michele_laino):
then:
volume = \(24 \times 7=...?\)
OpenStudy (shaleiah):
168
OpenStudy (michele_laino):
that's right!
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OpenStudy (shaleiah):
That's the total volume ? :)
OpenStudy (michele_laino):
yes!
OpenStudy (michele_laino):
|dw:1454018023389:dw|
OpenStudy (michele_laino):
it is a pyramid, so we have to apply this formula:
\[\Large volume = \frac{{\left( {base\;area} \right) \times height}}{3}\]
OpenStudy (michele_laino):
now, we have:
base area = \(6 \times 6=...?\)
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OpenStudy (michele_laino):
it is the area of a square
OpenStudy (shaleiah):
\[\frac{ 1 }{ 2 }*(36)(8)\]
OpenStudy (michele_laino):
more precisely, we can write this:
\[\Large volume = \frac{{\left( {base\;area} \right) \times height}}{3} = \frac{{36 \times 8}}{3} = ...?\]
OpenStudy (shaleiah):
96 :)
OpenStudy (michele_laino):
that's right! :)