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Mathematics 18 Online
OpenStudy (shaleiah):

@Michele_Laino

OpenStudy (michele_laino):

we have to compute the area of the base triangle

OpenStudy (michele_laino):

as first step, of course

OpenStudy (michele_laino):

the volume is not 96 cm^3

OpenStudy (shaleiah):

Alright, what formula should I apply?

OpenStudy (michele_laino):

here it is: \[\Large volume = \left( {base\;area} \right) \times height\]

OpenStudy (michele_laino):

|dw:1454017741013:dw| base area= \((6 \times 8)/2=...?\)

OpenStudy (shaleiah):

24

OpenStudy (michele_laino):

then: volume = \(24 \times 7=...?\)

OpenStudy (shaleiah):

168

OpenStudy (michele_laino):

that's right!

OpenStudy (shaleiah):

That's the total volume ? :)

OpenStudy (michele_laino):

yes!

OpenStudy (michele_laino):

|dw:1454018023389:dw|

OpenStudy (michele_laino):

it is a pyramid, so we have to apply this formula: \[\Large volume = \frac{{\left( {base\;area} \right) \times height}}{3}\]

OpenStudy (michele_laino):

now, we have: base area = \(6 \times 6=...?\)

OpenStudy (michele_laino):

it is the area of a square

OpenStudy (shaleiah):

\[\frac{ 1 }{ 2 }*(36)(8)\]

OpenStudy (michele_laino):

more precisely, we can write this: \[\Large volume = \frac{{\left( {base\;area} \right) \times height}}{3} = \frac{{36 \times 8}}{3} = ...?\]

OpenStudy (shaleiah):

96 :)

OpenStudy (michele_laino):

that's right! :)

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