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Mathematics 7 Online
OpenStudy (anonymous):

Prove the following trig identity In comments to make it clearer

OpenStudy (anonymous):

\[\frac{ \sin 3x+\sin x }{ \sin 3x-\sin x }=\frac{ 2 }{ 1-\tan ^{2}x }\]

OpenStudy (anonymous):

@jhonyy9 can you help me with this one too?

jhonyy9 (jhonyy9):

so depend from what part you wan to go on what part ?

jhonyy9 (jhonyy9):

sin3x=sin(2x+x) = ?

jhonyy9 (jhonyy9):

can you calculi it using formula sin(a+b) = ?

OpenStudy (anonymous):

Yeah I tried that but it became hideously complicated, so I stopped with that Is there a more efficient way that you know of?

OpenStudy (fifciol):

I think there is no simpler way, I did it by first apllying sin(a+b) formula, then reducing terms to sines, and at the end dividing by cos^2x to get the right hand side. If you want calculations, just let me know :)

OpenStudy (jdoe0001):

yeap.... I checked the RHS, no dice, it's about just as lengthy

OpenStudy (anonymous):

Alright thanks @Fifciol

OpenStudy (anonymous):

And yeah @jdoe0001 working the RHS would have too many different processes to unsimplify it and get the answer you need

OpenStudy (anonymous):

Hey @fifciol I'm stuck at -4sin^2x+4/-4sin^2+3 can you help?

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