Question

Please help!!! Will fan and medal!!!

Question attached in comments.

Answer 1

I think it's \[\frac{ 4b-12 }{b^2-6b+9 }\]

Answer 2

Can you simplify 4b-12?

Answer 3

that is a good first step
maybe you can factor and cancel

Answer 4

Uhm... 4-12= -8... would it be -8b?

Answer 5

^ yeah by factoring I mean
and also do that to the denominator

Answer 6

No you can't combine 4 and -12 because the 4 has a b

Answer 7

try factoring and simplifying

Answer 8

I thought the denominator stayed the same?

Answer 9

Not necessarily
It has to be simplified
And in this case it can be simplified

Answer 10

How can I factor them if none of them have like terms?

Answer 11

not to butt in, but you need to back up a second
you can factor \[4b-12\] but you cannot subtract \(12\) from \(4b\) and get for example \(-8b\) because they are not like terms
they do have a common facctor of 4, though, so you can "factor it out" as the math teachers say

Answer 12

Have you learned factoring quadratics yet?

Answer 13

And yeah what @satellite73 said

Answer 14

Somewhat but I'm not good at it...

Answer 15

Umm @satellite73 can you take over, I need to go and don't want to leave him hanging
Thanks!

Answer 16

@jhonyy9

Answer 17

Could you help if satellite can't?

Answer 18

the numerator is \[4(x-3)\]

Answer 19

that is what you get when you factor out the common factor of 4
do you know how to factor \[b^2-6b+9\]?

Answer 20

b^2-b?

Answer 21

i guess the answer is "no"

Answer 22

\[b^2-6b+9\] is a perfect square , it is \((b-3)^2\) or \((b-3)(b-3)\)
you should learn to recognize a perfect square like \[x^2-4x+4=(x-2)^2\] and \[x^2+16x+64=(x+8)^2\]

Answer 23

so you are looking at \[\frac{4(b-3)}{(b-3)(b-3)}\] cancel the common factor of \(b-3\) top and bottom

Answer 24

wait does that mean the final answer is \[\frac{ 4 }{ (b-3) }\]

Answer 25

yes it does

Answer 26

do i need the () ?

Answer 27

no

Answer 28

\[\frac{4}{b-3}\] is fine