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Mathematics 21 Online
OpenStudy (samigupta8):

The order of differential equation of family of circles touching two given circles externally is....

OpenStudy (yummy123):

Are there any answer choices

OpenStudy (samigupta8):

Yes they are A)1 B)2 C)3

Parth (parthkohli):

I swear this question makes no sense to me.

Parth (parthkohli):

Like where's the differential equation?

OpenStudy (yummy123):

I know right

OpenStudy (yummy123):

And it doesnt make sence

OpenStudy (samigupta8):

That's what we need to find....

OpenStudy (samigupta8):

Actually the fact i know is that the locus of the centre of family of circles is a hyperbola...

OpenStudy (samigupta8):

Bt after this i m unable to get what to do next ...i mean how to proceed...

Parth (parthkohli):

there are no derivatives involved here lol i guess

OpenStudy (yummy123):

what grade is this

OpenStudy (samigupta8):

12th...

OpenStudy (yummy123):

is your profile picture you

OpenStudy (samigupta8):

@parthkohli there is obviously derivative whenever any function exists...u will study it later...:)

OpenStudy (priyar):

u can obtain a diff eq only after getting a family of ciecles.. eq with constants..then u keep differentiating it to remove all the constants..and u will have a diff eq

OpenStudy (priyar):

*circles

OpenStudy (yummy123):

sorry i dont know

OpenStudy (samigupta8):

Do u want to say thT i shud solve it using differential of general hyperbolA ...?

OpenStudy (priyar):

i am not sure about the family of circles..part..did u do that part..?

OpenStudy (samigupta8):

It is definitely going to be a hyperbola ..

OpenStudy (samigupta8):

I mean the centre of those circles lie on a hyperbol

OpenStudy (priyar):

how did u find that out?

OpenStudy (samigupta8):

It's easy u know dis fact that hyperbola is locus of points whose difference from two fixed point is a constant quantity...

OpenStudy (priyar):

yeah

OpenStudy (samigupta8):

Dat's how v get it...

OpenStudy (samigupta8):

Since the two circles R fixed n we have been given that the circle touches two circles externally then u can simply say that Let radius of circle be r n that of fixed circles be r1 n r2 then r+r1 will be the distance between the circle n C1 n similarly r+r2 will be for another circle C2

OpenStudy (samigupta8):

Noe subtract the two n we get r1-r2 which is a constant quantity...

OpenStudy (samigupta8):

@hartnn pls help...

OpenStudy (priyar):

i don't think i would be of much help..maybe i can help to arrive at the diff eq after u frame the family of circles eq..(even i think its a hyperbola..if thats correct for sure then the order is 2 for sure!!)

OpenStudy (samigupta8):

Yup ...even i m getting the same if we consider it to be a general hyperbola

OpenStudy (samigupta8):

Bt the ans is not matching...

OpenStudy (priyar):

oh..ok i'll try and let u know..

OpenStudy (samigupta8):

Fine....thanks anyways

OpenStudy (priyar):

hey wait!

OpenStudy (samigupta8):

Yaa ...

OpenStudy (priyar):

we made a mistake in thinking its a hyperbola..only the locus of the "centre" of the family of circles will be in the form of a hyperbola..right?!

OpenStudy (priyar):

but the are asking for the equation of the circle...

OpenStudy (samigupta8):

Yess...i know dis thing ..

OpenStudy (samigupta8):

Okk...bt what will be the equation of circle....then..

OpenStudy (priyar):

we have only its centre..we need radius

OpenStudy (samigupta8):

V know its centre is lying on hyperbola n wt about its radius

OpenStudy (priyar):

i wrote the same!!

OpenStudy (samigupta8):

How to get it now?

OpenStudy (samigupta8):

Lol...

OpenStudy (priyar):

lemme think..

OpenStudy (samigupta8):

K

OpenStudy (samigupta8):

U ther??

OpenStudy (samigupta8):

@parthkohli wud u like to help...

OpenStudy (priyar):

i didn't get any idea still..

OpenStudy (samigupta8):

It"s okk...

OpenStudy (priyar):

hmm..

OpenStudy (anonymous):

so as you know the locus of center of the circle is hyperbola. (as you detailed above). if we cosider the the center of the circle as (a,b). than we can also write "b" as = b=>f(a) (b in terms of a. so, r=f(a,b), r is radius here. the equation of this circle is linear, so order of differential equation of this circle will be "1". ok

OpenStudy (samigupta8):

How did u say r is a function of (a n b)?

OpenStudy (samigupta8):

@newtonson will u pls...tell?

OpenStudy (amity):

Answer is 3

OpenStudy (samigupta8):

No

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