Please help!!! Will fan and medal!!! Question attached in comments!!!!
so..hmm ok.. what's the LCD?
5?
hmm have you covered sum of fractions or rationals yet?
I can add these generally but not subtract..
well, adding and subtracting is pretty much the same thing if you think of 2 - 3 is really 2 + (-3)
same as last time. because the bottoms are the same focus on the top
all you are going to focus on is 4d-20
can you simplify 4d-20 at all?
Uhm... -16d???
nope. you cat because its not equal to anything
Need to factor the bottom
i agree
not yet actually.
you combine the tops and then figure out what to cancel out.
wait is te bottom not d^2-10d+25?
Sounds like a plan
I'm confused ;-;
no not really. because you can take out some of the -10d :)
*cough*
wait so ow do we combine 4d nd 20?
litle brother sorry
hmmm if you haven't covered common factoring and quadratic factoring, and/or FOIL or even LCD I'd suggest this is a good time to start off there to begin with
@jdoe0001 my bro is acting up; can you take care of this?
who?
little brother
hmm well...hmmm put on the simpsons video =P
I've covered all of those I don't know how it works with this tough
lol he's screaming at the top of his lungs. gtg sry!
it's okay.
Where did you get too?
We still have to combine te 4d-20
oh, you wat to factor it. do the two numbers have any common factors?
*want
hmmm hmm... ok... so. hmm let us start off notice the denominators what do you think is the LCD?
4 = 2*2, 20 = 2*10 = 2*2*5
Uhm, where does the 2*2*2 come from?
d^2 -10d +25 = d*d -5d-5d +(-5)(-5) = ? factorized completly - these will help you ?
\[2\cdot2 =4\]
We are looking at all the factors of 4 and 20 to find any common factors
First of all, the denominators are the SAME for both fractions, which greatly simplifies your work. Simply find the difference between 4d and 20, and write your (factored) result over the given denom. Unless you want to try to reduce this, y ou're done! Please show all work.
the denom factors --> must reduce
I'm not sure how tto factor 4d-20, and the above explanations are confusing me.
try and factor out a 4.
4(d - ?)
Hint: what's 20/4?
5
I said 5 earlier but rhonda told me no
Nice, 4(d-5) now lets use this as a hint to factor the bottom
5+5+5+5=20
i.e. \[4\cdot5=20\]
Redcan: Let's look at the whole denom., a quadratic. Help WhatEven choose an appropriate strategy for factoring this denom.
WhatEven: which methods of factoring quadratics are most familiar for you?
I think we are still working on understanding the top
Um. Combining like terms.
whats up what do u guys need
Mikey236333: Redcan and WhatEven are doing fine on their own. You're welcome to watch if you wish.
Where we are\[\frac{4(d-5)}{d^2-10+25}\]
Nice work, Redcan. WhatEven: again, what methods do you know for factoring quadratics, such as the denominator of this rational fraction?
I had said combining like terms but that's not right... I know what factoring is Im not good at it though I'm not sure wat our first step is.
@mathmale @Redcan ? Did everyone really leave? :( Not cool
help??
I could really use some
did you get this one? it is identical to one we did yesterday
are you at this step now\[\frac{4(d-5)}{d^2-10+25}\]?
Yes satellite that is where I am
WHat help
Question ?
ok do you remember the one we did almost identical where the denominator was a perfect square, so you could factor and then cancel the common factor top and bottom?
i think we had just about the same thing \[\frac{4(d-3)}{d^2-6d+9}\]
then we factored the denominator as \[\frac{4(d-3)}{(d-3)(d-3)}\] and then cancelled
I kind of remember... Can you walk me through it again? :(
sure but i bet you can do it for yourself we had \[\frac{4(d-3)}{d^2-6d+9}=\frac{4(d-3)}{(d-3)(d-3)}=\frac{4}{d-3}\]
you have \[\frac{4(d-5)}{d^2-10d+25}\] factor the denominator like we factored the one above, making a slight adjustment since \(5^2=25\) rather than \(3^2=9\)
Woah.. where did those two fractions come from? are we omitting the original denominator?
you confused me there, i had to scroll up \[e62-10d+25\]IS the originai denominator your job is to factor it
oops i meant \[d^2-10d+25\]is the original denominator
So to factor it what is our first step?
recognize two things
Does this have to do with 5 again?
first of all, the denominator is a perfect square since \(-2\times -5=-10\) and \((-5)^2=25\) also notice that since this problem was made up by a math teacher, you can bet your lunch money that the factor of \(d-5\) in the numerator will cancel with a factor of \(d-5\) in the denominator
So then our answer is \[\frac{ 4 }{d-5 }\] ?
which is a long winded was of saying, that just like \[d^2-6d+9=(d-3)(d-3)\] also \[d^2-10d+25=???\]
yes dear it is !
took two hours to get there, but that is it
I think I kind of get it... can I tag you if I need help again? And I'm sorry I just don't get where the numbers are coming from most the time and it confuses me..
sure no problem
Tank you so much.
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