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Mathematics 8 Online
OpenStudy (anonymous):

Please help!!! Will fan and medal!!! Question attached in comments.

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

IDENTICAL to the one we just did earlier and yesterday by now i bet you can do it

OpenStudy (anonymous):

subtract in the top then factor out the 8 in the numerator the denominator is another perfect square, factor and cancel

OpenStudy (anonymous):

Ohh yea we divide 32 by 8

OpenStudy (anonymous):

So for the top it'd be 4(u-8)?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

and take a wild guess as to how the denominator factors ...

OpenStudy (anonymous):

oh woops no not \(4(u-8)\) but rather \(8(u-4)\)

OpenStudy (anonymous):

the common factor of \(8u\) and \(32\) is \(8\)

OpenStudy (anonymous):

so, as the math teachers say, you "factor it out"\[8u-32=8(u-4)\]

OpenStudy (anonymous):

now just like the last one the denominator is a perfect square, factor and cancel

OpenStudy (anonymous):

you can probably at this point guess what the answer is

OpenStudy (perfect14):

6u+16 is the denominator

OpenStudy (anonymous):

I know it's 8/u-4 I'm tring to see how 16 is eliminated though

OpenStudy (anonymous):

because just like last time it factors \[u^2-8u+16=(u-4)(u-4)\] and the common factor of \(u-4\) cancels top and bottom

OpenStudy (anonymous):

you gotta get this factoring thing together because they are using it alot

OpenStudy (anonymous):

I think I see... And I'm trying I'm sorry :( I'm really trying it's just hard for me :(

OpenStudy (anonymous):

hey don't fret, it is not like you are born knowing it, you are learning it

OpenStudy (anonymous):

Wait 8/4-u was wrong D:

OpenStudy (anonymous):

grr that is because it is \[\frac{8}{u-4}\]

OpenStudy (anonymous):

not \[\frac{8}{4-u}\] which is different

OpenStudy (anonymous):

Dang it! See simple things like that get me too :'(

OpenStudy (anonymous):

ah you'll get it

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