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Mathematics 20 Online
OpenStudy (anonymous):

Please please help!!!! Will fan and medal!!!! Question attached in comments!!!!!

OpenStudy (anonymous):

I think it's \[\frac{ 3 }{ x-2 }\] but I don't know if I'm right.... @RhondaSommer @satellite73

OpenStudy (anonymous):

@Astrophysics @jhonyy9

OpenStudy (sweetburger):

do you know how to start off here?

OpenStudy (anonymous):

Divide 6 by 2..

RhondaSommer (rhondasommer):

mmhmm what do you get?

OpenStudy (anonymous):

3. Is it not \[\frac{ 3 }{ x-2 }\] ??????

OpenStudy (sweetburger):

Alright for these kinds of question you want to make sure that the denominators are equivalent. For this question they already are so its not to worry about. Start by just subtracting the numerator and leaving the denominator constant.

RhondaSommer (rhondasommer):

aka 2x+-6x=? put ? in the denominator

OpenStudy (anonymous):

... so -4 x? what?

OpenStudy (sweetburger):

I wrote that poorly there is no 6x its just 2x-6

OpenStudy (anonymous):

.... I'm lost... I really really thought i was right.....

OpenStudy (sweetburger):

factor out \[x^2-6x+9\] what do you get?

OpenStudy (anonymous):

x-2x+3?

OpenStudy (sweetburger):

It actually factors out to (x-3)(x-3)

OpenStudy (anonymous):

so it's \[\frac{ 2 }{ x-3 }\]

OpenStudy (sweetburger):

yes correct

OpenStudy (sweetburger):

good job

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