Question

An ice cube tray full of ice (125 g) at -5C is allowed to warm up to room temperature (22C). How much energy must be absorbed by the solid ice to reach this room temperature. For water: Heat of fusion = 334 J/g, Heat of vaporization = 2260 J/g, Heat capacity of solid water = 2.10 J/gC, Heat capacity of liquid water = 4.18J/gC.
NOTE: This problem is a three part problem. You must show all work

can someone solve this for me I have no idea how

Answer 1

help please

Answer 2

I see why this is tricky

Answer 3

you need to draw a phase transition diagram

Answer 4

whats that

Answer 5

how does that help?

Answer 6

sorry my x and y are reversed, making changes nows

Answer 7

different fomulae apply to temp increase and phase transtion

Answer 8

we see 3 segments on this graph, 2 temp increase and 1 phase transition

Answer 9

this is becuase the ice has to be at 0C before it melts and after it melted the temp has to increase to 22C

Answer 10

still with me?

Answer 11

yes

Answer 12

so do you know what fomula is for temp increase and what to use for phase transition

Answer 13

no

Answer 14

ok, so for temp increase we have Q=c*m*delta T

Answer 15

for phase transiton we have Q=Hf*m

Answer 16

what would I plug in then

Answer 17

so you don't know what the symbol means?

Answer 18

more things for you to memorize then

Answer 19

not really im really bad at this subject

Answer 20

Q is total heat absorbed, c is heat capacity, m is mass of matter. delta T is change in temp

Answer 21

Hf is heat of fusion

Answer 22

since we do not boil the water, heat of vap or Hv is irralavent here

Answer 23

im still not sure on how this is to be sloved

Answer 24

ok where are you stuck ?

Answer 25

at what to even plug in

Answer 26

mass of water 125g, starting temp -5C, end temp 0C, heat capacty of ice 2.1 j*g^-1*C^-1

Answer 27

correct?

Answer 28

lost

Answer 29

ok did you understand symbols on my equation?

Answer 30

yaa

Answer 31

now, do you know the values of the variables, except for the one we want to calculate of cuse

Answer 32

no

Answer 33

mass of water is 125g rihgt?

Answer 34

ya

Answer 35

heat capacity for ice is 2.1J/gC

Answer 36

I still don't get what to do with these numbers

Answer 37

you plug them in, obviously

Answer 38

how

Answer 39

for example in the first phase we have Q=mcdelta T

Answer 40

m is 125g, c is 2.1J/gC, delta T is 5C, NOT 27C

Answer 41

so Q is?

Answer 42

so I would do 125X2260/1

Answer 43

No

Answer 44

why would you use heat of vap when no vap happens

Answer 45

so ok, your problem is physics not math

Answer 46

You need to understand when and where to use what

Answer 47

Q is 1312.5

Answer 48

great, but this is only phase I because we only bring the ice to 0C which is the mp

Answer 49

so next step is to melt the ice

Answer 50

and what is the heat for this process?

Answer 51

idk

Answer 52

the equation is Q=m*Hf, you know m and Hf, so what is Q?

Answer 53

whats hf

Answer 54

Heat of fusion

Answer 55

I need to go cook dinner now, so stay here, I'll be right back

Answer 56

I'm back, any idea?

Answer 57

41750

Answer 58

great, and phase 3?

Answer 59

no hint this time

Answer 60

divide the two phases

Answer 61

well, no but why would you say so?

Answer 62

I don't know now at this point

Answer 63

well phase 3 is the same process as phase 1 which is (), the equation for this process is (), the c in the eqaution stands for (), but not (). the value of c is () the change in temperature is () the heat absored during phase 3 is () the heat absorbed during the entire process ( phase1 and 2 and 3) is ().

Answer 64

try fill in the blanks, I can give you hints if you stuck

Answer 65

so I X the two phases to get the 3 one

Answer 66

no, I said try fill in the quiz I jsut give you, it will help you understand the ideas behind this question. it won't help you if I just told you the answer

Answer 67

sorry computer acting up and alright im try get it

Answer 68

if you got stuck anywhere just ask