Two violinists are trying to tune their instruments in an orchestra. One is producing the desired frequency of 440.0 Hz. The other is producing a frequency of 453 Hz. By what percentage should the out-of-tune musician change the tension in his string to bring his instrument into tune at 440.0 Hz?
So the first thing you need to ask is what is the difference of 440hz from 453hz?
13
Right. So now the question is what percentage so we can write out an equation to look like this: 400 * x = 13 where x is the percentage needed to get us 13 hz
Oops my bad i just woke up i mean 453*x=13
So what would x equal then?
so are you saying to divide 13 by 400, and then multiply by 100 to get the percent
Yes, but 453 not 400 my mistake :P
And so now you know it's around 2.9 percent so reverse check it: 453*0.029 = around 13 which 453-13 = 440 which is what we were looking for
Alright thanks I get it! I tried using some explanation on yahoo and it was crap. Have a nice day.
Mhm. Just be careful w/the answer cause it may want it rounded to a whole number/tenth ect :P
okay
2.9 was wrong the answer is 5.7%
I'm sorry. That should be the way though. Even using a percentage difference calculator is gives 2.9 percent so i really dont know how else that could be wrong
Does it give an explanation?
It gives no explanation but there is that yahoo answers link that I couldn't understand. Maybe you could take a look at it. https://answers.yahoo.com/question/index?qid=20100502081857AAQQ2AG
Ok well I'm terribly sorry but ive never seen an equation like that. However, it should be (440/453)^2 * 100 then 100 - the answer you get from the left which equals the 5.7%.
alright thanks!
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