Question

Hello,

I need to graph y = sec(1/3x) - 5

I know that the amplitude is 1, the period is 6pi, but I don't know what else I have to do

I do know that I have to replace it at

y = cos(1/3x)-5

I need to find 5 parts, making 6π/4 = 3π/2

Any ideas?

Answer 1

I'd suggest that you graph y=sec x first. We'll take care of the rest of your posted problem later.

Answer 2

It says i'm not allowed to graph the sec, so I have to do this by hand and step by step :P

For part one of the x, I got

x = 1, therefore y will be 0+1 -5 = (0,-4)

Part two

x = 3π/2, y = -1 - 5 = (3π/2, -6)

Answer 3

I believe I made a mistake with the quarter periods...

I checked at demos making the parts being (0,-4); (3π,-6);(6π,-4) any idea on how to fix the quarter period? For some reason I keep adding 3π/2 per quarter, not 3π

Answer 4

I still think you should graph y=sec x = 1 / cos x.
Where the cosine is zero, the secant is undefined.
Where the cosine is +1, the secant is also +1.

Please do a rough graph using the Draw utility.

Please clarify: what did you intend "1/3x" to signify? 1 / (3x) ? (1/3) x?