Question

k = (Squared root 2k-4) + 2. solve for k

Answer 1

\(k = \sqrt{2k - 4} + 2\)

Is this the problem?

Answer 2

yup. so would it be k-2 = squared root 2k-4??

Answer 3

You need to have the square root alone on one side, so that when you square both sides you get rid of the square root.

Answer 4

@akausen You were correct.
Subtract 2 from both sides.
@hs_beauty You are correct.

Answer 5

(k-2)^2 = 2k-4

Answer 6

Will I always have to use the quadratic formula??

Answer 7

We're not ready for the quadratic formula yet, but soon.

\((k - 2)^2 = (\sqrt{2k - 4} )^2\)

\((k - 2)^2 = 2k - 4\)

Now calculate the square of the binomial on the left side.

Answer 8

would it be k^2 - 4??

Answer 9

No.

\((k - 2)^2 = 2k - 4\)

\((k - 2)(k - 2) = 2k - 4\)

You can rewrite the square of the binomial as I did above.
Now use FOIL.

Answer 10

k^2-4k+4?