You flip a coin three times. What is the probability that at least one of the outcomes will be tails?
Would this be me multiplying 1/2 * 1/2 * 1/2 ? The thing that confuses me is when it says at least once.
Have you considered drawing the set of all possible outcomes? Three independent tosses with 2 possible outcomes per toss ... ?
I just picture flipping a coin threetimes. The probability of getting tails each time is 1/2
Make a probability tree which feature every outcome. Now find the probability of any outcome which have tails and then add every probability together.
in this problem there is no need of writing all: the opposite of at least one is 0 times,so first calculate the opposite this is 1/2*1/2*1/2=1/8.. now when you know the opposite ,for your statement 1-1/8=7/8
if you don't do this way,you should calculate tail 1 time,2 time,3 time and sum
Okay, so the outcome would 7/8?
yeah
Okay. Hmm. I understand that.
you can write every occurence but that takes long.this one is simpler and shorter
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Actually looking back at my notes, it does look like I have to subtract from one.
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