Question

theorem: A line parallel to one side of a triangle divides the other two proportionately.


In the figure below, segment DE is parallel to segment BC and segment EF is parallel to AB:

Answer 1

Segment BF = 16
Segment BD = 18
Segment BD = 20
Segment BF = 15

Answer 2

@welshfella

Answer 3

What is the question again?, do you want to prove the theorem? or find unknown lengths?

Answer 4

Which statement can be proved true using the given theorem?

Answer 5

oh ok, for the parallel line EF, the statement theorem means: \[\frac{ 15 }{ 25 }=\frac{ BF }{ 30 }\]

Answer 6

There is an analogue for the parallel line DE involving DB

Answer 7

in order to find my answer do i cross multiply?

Answer 8

yep, BF=\[BF= 30*\frac{ 15 }{ 25 }\] but that one isnt in your answers

Answer 9

so i can cross out the first one and the last one?

Answer 10

Yep, , BF is 18, now for BD : we are cutting AC, and AB with the parallel line DE

Answer 11

so 12 is to BD like 15 is to 25, formulate the ratios like I did for the other one, and then you are done, there is a correct answer

Answer 12

the answer i the third one :)

Answer 13

thanks.

Answer 14

No problemo :D