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Mathematics 9 Online
OpenStudy (daniellelovee):

From a standard deck of playing cards, a card is selected at random. Find the probability of the event The card selected is a heart or a queen

OpenStudy (daniellelovee):

@ganeshie8 can you help me understand how to solve?

OpenStudy (daniellelovee):

@zepdrix

zepdrix (zepdrix):

Let's get some information organized. How many hearts in the deck? :)

OpenStudy (daniellelovee):

no 13 sorry

zepdrix (zepdrix):

Ok good. And 4 queens.

OpenStudy (daniellelovee):

yes

zepdrix (zepdrix):

This word OR is telling us that we want one of these 13 cards OR one of these 4 cards. It's less restrictive than the AND word. So we simply add our two groups together. 13 + 4 = 17 But we have a slight problem. There was an overlap! Because one of our queens is one of our hearts, right?

zepdrix (zepdrix):

Because there is a queen of hearts*

OpenStudy (daniellelovee):

yes

zepdrix (zepdrix):

So we have to subtract the `intersection of these groups`. P(heart OR queen) = P(heart) + P(queen) - P(intersection) P(heart OR queen) = 13 + 4 - 1

zepdrix (zepdrix):

And if we want a probability, we need to divide this number of cards by the `total`.

OpenStudy (daniellelovee):

therefore it will be 16/52?

OpenStudy (daniellelovee):

4/13?

zepdrix (zepdrix):

yay good job \c:/

OpenStudy (daniellelovee):

alright thank you so much for helping me understand :)

zepdrix (zepdrix):

np

OpenStudy (daniellelovee):

what would it be if there was no intersection? would it just n=be 17/52?

OpenStudy (daniellelovee):

@zepdrix

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