From a standard deck of playing cards, a card is selected at random.
Find the probability of the event
The card selected is a heart or a queen
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OpenStudy (daniellelovee):
@ganeshie8 can you help me understand how to solve?
OpenStudy (daniellelovee):
@zepdrix
zepdrix (zepdrix):
Let's get some information organized.
How many hearts in the deck? :)
OpenStudy (daniellelovee):
no 13 sorry
zepdrix (zepdrix):
Ok good.
And 4 queens.
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OpenStudy (daniellelovee):
yes
zepdrix (zepdrix):
This word OR is telling us that we want one of these 13 cards OR one of these 4 cards. It's less restrictive than the AND word.
So we simply add our two groups together.
13 + 4 = 17
But we have a slight problem.
There was an overlap!
Because one of our queens is one of our hearts, right?
zepdrix (zepdrix):
Because there is a queen of hearts*
OpenStudy (daniellelovee):
yes
zepdrix (zepdrix):
So we have to subtract the `intersection of these groups`.
P(heart OR queen) = P(heart) + P(queen) - P(intersection)
P(heart OR queen) = 13 + 4 - 1
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zepdrix (zepdrix):
And if we want a probability,
we need to divide this number of cards by the `total`.
OpenStudy (daniellelovee):
therefore it will be 16/52?
OpenStudy (daniellelovee):
4/13?
zepdrix (zepdrix):
yay good job \c:/
OpenStudy (daniellelovee):
alright thank you so much for helping me understand :)
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zepdrix (zepdrix):
np
OpenStudy (daniellelovee):
what would it be if there was no intersection? would it just n=be 17/52?